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miss Akunina [59]
3 years ago
7

Simplify the expression:3(7r + 1) =​

Mathematics
2 answers:
kozerog [31]3 years ago
8 0

Answer:

21r +3

Step-by-step explanation:

3(7r + 1) =​

Distribute

3*7r +3*1

21r +3

Andreas93 [3]3 years ago
4 0

Answer:

21r+3

Step-by-step explanation:

3(7r + 1)

Use the distributive property.

This property is normally used when the 2 numbers inside of the parentheses can not be added easily.

3*7r+3*1

21r+3

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Celine ate brunch at a restaurant. The bill came to $72.80. If she left a 15% tip, what was the total cost of her brunch?
DedPeter [7]

Answer:

<em>$83.69</em>

Step-by-step explanation:

Given the following

Initial Cost of the brunch = $72.80

Percentage tip = 15%

Tip paid = 15% of $72.60

Tip paid = 0.15 * 72.60

Tip paid = $10.89

Total cost of brunch =  $72.80 + $10.89

Total cost of brunch = $83.69

<em>Hence the total cost of her brunch is $83.69</em>

7 0
2 years ago
Find the distance between points (2, 9) and (5, 4) to the nearest tenth​
Troyanec [42]

Answer:

Distance = 5.8

Step-by-step explanation:

d=\sqrt{(4-9)^{2} } { (5-2)} ^{2} \\

d = -5^{2}  + 3^{2}

d= 25 + 9

d= \sqrt{34}

distance = 5.8

3 0
3 years ago
Let X denote the amount of time a book on two-hour reserve is actually checked out, and suppose the cdf is the following. F(x) =
Troyanec [42]

Answer:

a) P (x <= 3 ) = 0.36

b) P ( 2.5 <= x <= 3  ) = 0.11

c) P (x > 3.5 ) = 1 - 0.49 = 0.51

d) x = 3.5355

e) f(x) = x / 12.5

f) E(X) = 3.3333

g) Var (X) = 13.8891  , s.d (X) = 3.7268

h) E[h(X)] = 2500

Step-by-step explanation:

Given:

The cdf is as follows:

                           F(x) = 0                  x < 0

                           F(x) = (x^2 / 25)     0 < x < 5

                           F(x) = 1                   x > 5

Find:

(a) Calculate P(X ≤ 3).

(b) Calculate P(2.5 ≤ X ≤ 3).

(c) Calculate P(X > 3.5).

(d) What is the median checkout duration ? [solve 0.5 = F()].

(e) Obtain the density function f(x). f(x) = F '(x) =

(f) Calculate E(X).

(g) Calculate V(X) and σx. V(X) = σx =

(h) If the borrower is charged an amount h(X) = X2 when checkout duration is X, compute the expected charge E[h(X)].

Solution:

a) Evaluate the cdf given with the limits 0 < x < 3.

So, P (x <= 3 ) = (x^2 / 25) | 0 to 3

     P (x <= 3 ) = (3^2 / 25)  - 0

     P (x <= 3 ) = 0.36

b) Evaluate the cdf given with the limits 2.5 < x < 3.

So, P ( 2.5 <= x <= 3 ) = (x^2 / 25) | 2.5 to 3

     P ( 2.5 <= x <= 3  ) = (3^2 / 25)  - (2.5^2 / 25)

     P ( 2.5 <= x <= 3  ) = 0.36 - 0.25 = 0.11

c) Evaluate the cdf given with the limits x > 3.5

So, P (x > 3.5 ) = 1 - P (x <= 3.5 )

     P (x > 3.5 ) = 1 - (3.5^2 / 25)  - 0

     P (x > 3.5 ) = 1 - 0.49 = 0.51

d) The median checkout for the duration that is 50% of the probability:

So, P( x < a ) = 0.5

      (x^2 / 25) = 0.5

       x^2 = 12.5

      x = 3.5355

e) The probability density function can be evaluated by taking the derivative of the cdf as follows:

       pdf f(x) = d(F(x)) / dx = x / 12.5

f) The expected value of X can be evaluated by the following formula from limits - ∞ to +∞:

         E(X) = integral ( x . f(x)).dx          limits: - ∞ to +∞

         E(X) = integral ( x^2 / 12.5)    

         E(X) = x^3 / 37.5                    limits: 0 to 5

         E(X) = 5^3 / 37.5 = 3.3333

g) The variance of X can be evaluated by the following formula from limits - ∞ to +∞:

         Var(X) = integral ( x^2 . f(x)).dx - (E(X))^2          limits: - ∞ to +∞

         Var(X) = integral ( x^3 / 12.5).dx - (E(X))^2    

         Var(X) = x^4 / 50 | - (3.3333)^2                         limits: 0 to 5

         Var(X) = 5^4 / 50 - (3.3333)^2 = 13.8891

         s.d(X) = sqrt (Var(X)) = sqrt (13.8891) = 3.7268

h) Find the expected charge E[h(X)] , where h(X) is given by:

          h(x) = (f(x))^2 = x^2 / 156.25

  The expected value of h(X) can be evaluated by the following formula from limits - ∞ to +∞:

         E(h(X))) = integral ( x . h(x) ).dx          limits: - ∞ to +∞

         E(h(X))) = integral ( x^3 / 156.25)    

         E(h(X))) = x^4 / 156.25                       limits: 0 to 25

         E(h(X))) = 25^4 / 156.25 = 2500

8 0
3 years ago
Write the quadratic equation y=x^2-6+7 in vertex form
antoniya [11.8K]
Half the x-coefficient is -3, so the equation needs to be rearranged into a form that looks like
  x² -6x +(-3)² + [something]
You can get there by adding and subtracting 9 from the original equation.
  y = x² -6x +9 +7 -9 . . . . . 9 added and subtracted
  y = (x² -6x +9) -2
The quantity in parentheses is a perfect square, so we can write the equation in the desired form as ...
  y = (x -3)² -2
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3 years ago
What is two times two and one third
eduard
The answer is 14/3 or 4 and 2 thirds
4 0
3 years ago
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