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EleoNora [17]
3 years ago
14

For school lunch students have 3 meat choices (beef, chicken, or fish), 2 potato choices (mashed or fried), and 3 drink choices

(milk, juice, or water).
How many different combinations could students create using one meat, one potato, and one drink?
- 8
- 9
- 11
- 15
- 18
Mathematics
2 answers:
ioda3 years ago
8 0

Answer:

18

Step-by-step explanation:

3 \times 2 \times 3

That will give you 18 which is the answer

ZanzabumX [31]3 years ago
8 0
18 , if you multiply 3 x 3 x 2 = 18

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The figure shows a carpeted room. How many square feet of the room are carpeted?
Nadya [2.5K]

Answer:

Hello there, the answer would be

Step-by-step explanation:

We cut the figure into two different shapes.

Since on one side it is 4 feet and the height is seven, we cut right there.

So the bottom figure is now 4 x 5 = 20

The top figure is cut with 3 height left, So all we do is just multiply.

8 x 3 = 24.

20+24=44.

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2 years ago
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Answer:

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Does the point (–9, 8) satisfy the equation y = –x + 1?
Darina [25.2K]

Answer:

1. 3x+3y=9 since it is a coinciding line.It is equivalent because all the terms are multiplied by 3 from the original equation.

2. x-4=3x+4

x=3x+8

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8 0
2 years ago
A researcher was testing the number of popcorn kernels that popped out of a mini bag of 100 kernels after being cooked for the s
Lelechka [254]

Answer:

The percentage of the bag that should have popped 96 kernels or more is 2.1%.

Step-by-step explanation:

The random variable <em>X</em> can be defined as the number of popcorn kernels that popped out of a mini bag.

The mean is, <em>μ</em> = 72 and the standard deviation is, <em>σ</em> = 12.

Assume that the population of the number of popcorn kernels that popped out of a mini bag follows a Normal distribution.

Compute the probability that a bag popped 96 kernels or more as follows:

Apply continuity correction:

P( X\geq 96)=P( X>96+0.50)

                 =P( X>96.50)\\=P(\frac{X-\mu}{\sigma}>\frac{96.50-72}{12})\\=P(Z>2.04)\\=1-P(Z

*Use a <em>z</em>-table.

The probability that a bag popped 96 kernels or more is 0.021.

The percentage is, 0.021 × 100 = 2.1%.

Thus, the percentage of the bag that should have popped 96 kernels or more is 2.1%.

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