Break the numbers under the radical into perfect squares: $\sqrt{2^2*2^2*2*x^2*x^2*z}$ . Take the perfect squares out: you have two 2's, and 2 x's, on the outside of the radical with 2 and z leftover: $3*2*2*x*x*\sqrt{2*z}$ . Multiply everything together to get $12x^2\sqrt{2z}$ .

7 0

3 years ago

Graph tthe system of equations below on a piece paper. what is the solution y=2x-3 y=-x+3

Katen [24]

Answer:

Look at the explanation.

Step-by-step explanation:

Start y=-2x-3 at the Y -3 and X 0, then go up two and to the right one, like a staircase. For y=-x+3 start on Y 3 and X 0 and go down 1 x and 1 y like a downstair staircase with 1 unit down.

4 0

3 years ago

Solve the triangle for all missing sides and angles

Mama L [17]

Answer:

x = 35

C = 18.92

A = 71.07

Step-by-step explanation:

Use the Pythagorean theorem to find the unknown side.

$a^{2} +b^{2} =c^{2} \\\\\\12^{2} +x^{2} =37^{2} \\x^{2} = 37^{2}-12^{2}\\x=35$

For Angle C

The angle C can be found using the inverse sine function.

C=arcsin(opp/hyp)

C=arcsin(12/37)

C=18.92

For Angle A

The sum of all the angles in a triangle is 180 degrees.

A + 90 + 18.92 = 180

A = 71.07

8 0

3 years ago

Find the x-intercepts for the parabola defined

Inessa05 [86]

Answer:

<h2>Explanation:</h2>

In this exercise we have the following equation of a parabola:

$y=2x^2-12x+10$

So our goal is to find the x-intercepts. We can find this setting $y=0$ , so:

$2x^2-12x+10=0$

Taking 2 as common factor:

$2(x^2-6x+5)=0$

Hence this is a Non-perfect Square Trinomial. To factor out this, let's choose two numbers such that:

The sum is -6
The product is 5

Those two numbers are:

-1 and -5

Because:

Sum: -6
Product: 5

So this equation can be written as:

$x^2 + (a + b)x + ab=(x + a)(x + b) \\ \\ a=-1 \\ b=-5 \\ \\ x^2-14x+24=(x-(-1))(x-(-5))=0 \\ \\ (x+1)(x+5)=0 \\ \\ So \ the \ solutions \ are: \\ \\ \boxed{x=-1 \ and \ x=-5}$

<h2>Learn more:</h2>

Solutions to quadratic equation: brainly.com/question/13742278#

#LearnWithBrainly

5 0

3 years ago