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2 years ago

#10 solve the equation 1/3m - 7 = 5

1 answer:

5 0

(1/3) m - 7 = 5
(1/3) m - 7 + 7= 5 + 7 ⇒⇒⇒ edit 7 to both sides
(1/3) m = 12
3 * (1/3) m = 12 * 3 ⇒⇒⇒ multiply both sides by 3
∴ m = 36

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How would I simplify 53-2(16/8*16-7)

Oduvanchick [21]

The simplified form of the expression is 3

<h3>Simplifying an Expression</h3>

From the question, we are to simplify the given expression

The given expression is

53 -2(16/8 * 16-7)

Simplifying

Using BODMAS

53 -2(16/8 × 16-7)

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Learn more on Simplifying an Expression here: brainly.com/question/3622770

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1 year ago

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2 years ago

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3 years ago

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Serga [27]

Answer:

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2 years ago

Read 2 more answers

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aleksklad [387]

Answer:

a.2nd quarter with 9 goals

b. 4.8 goals

c. 4 goals

Step-by-step explanation:

a. The mode is defined as the most appearing data point or the data point with the highest frequency..

From our data(for away goals):

1st quarter-2
2nd quarter-9
3rd quarter-7
4th quarter-4

Hence, the 2nd quarter has the mode for away goals with 9 goals.

b. Mean is defined as the average of a set of data points.

#We calculate the totals goals per quarter, sum over all quarters then divide by the number of games, 10:

$\bar x=\frac{1}{n}\sum{x_i}\\1^{st }_g=Away+Home=5+2=7\\\\2^{nd}_g=Away+Home=4+9=13\\\\3^{rd}_g=Away+Home=8+7=15\\\\4^{th}_g=Away+Home=9+4=13\\\\\bar x=\frac{1}{n}\sum{x_i}=\frac{1}{10}(7+13+15+13)=4.8$

Hence, the mean number of goals per quarter is 4.8 goals

c. To find the number of more home goals than away goals, we subtract from their summations as:

$g_m=\sum{g_h}-\sum{g_a}\\\\=(5+4+8+9)-(2+9+7+4)\\\\=26-22\\\\=4$

Hence, there are 4 more home goals than away goals.

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2 years ago