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3 years ago

Please the whole page 50 Points each. Please don't steal my points just because

Mathematics

1 answer:

boyakko [2]3 years ago

8 0

Answer:

Step-by-step explanation:

give

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Factor the expression. 4d + 12 Enter your answers in the boxes.

Dmitry_Shevchenko [17]

4d + 12 = 4(d + 3)
Basically, you just need to determine what 4d and 12 have in common. In this case, they both divide evenly by 4. Therefore 4 (d + 3) = 4d + 12 according to the distributive property.

5 0

3 years ago

Read 2 more answers

What is the answer to this math question?

oksano4ka [1.4K]

Answer:

The answer is option 3.

Step-by-step explanation:

First we have to find the area of both rectangle and triangle :

Rectangle,

$area = base \times height$

Let base = 9,

Let height = 3,

$area = 9 \times 3 \\ area = 27 \: {m}^{2}$

Triangle,

$area = \frac{1}{2} \times base \times height$

Let base = 3,

Let height = 3,

$area = \frac{1}{2} \times 3 \times 3 \\ area = \frac{1}{2} \times 9 \\ area = \frac{9}{2} \\ area = 4.5 \: {m}^{2}$

Lastly, in order to find the shaded region you have to substract the area of triangle from the area of rectangle :

$area = 27 - 4.5 \\ area = 22.5 \: {m}^{2}$

5 0

3 years ago

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Use matrix addition to solve this equation: B + 15 −7 4 0 1 2 = 1 2 12 4 0 2 b11 = b12 = b13 = b21 = 4 b22 = −1 b23 = 0

Arada [10]

Answer:

$b_{11}=-14,b_{12}=9,b_{13}=8,b_{21}=4,b_{22}=-1,b_{23}=0$

Step-by-step explanation:

The given matrix addition is

$B+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$

We need to find the elements of matrix B.

Let $B=\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}$

Substitute the value of matrix.

$\begin{bmatrix}b_{11}&b_{12}&b_{13}\\ b_{21}&b_{22}&b_{23}\end{bmatrix}+\begin{bmatrix}15&-7&4\\ 0&1&2\end{bmatrix}=\begin{bmatrix}1&2&12\\ 4&0&2\end{bmatrix}$