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3 years ago

44 * 9678 I will mark brainliest

Mathematics

2 answers:

Kisachek [45]3 years ago

7 0

Answer:

=425832

Step-by-step explanation:

i hope this helps :)

allsm [11]3 years ago

6 0

Answer:

425832

Step-by-step explanation:

I was trying as well gg

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What is the image point of (9,4) after a translation left 5 units and up 1 unit?

UNO [17]

Answer:

(4,5)

Step-by-step explanation:

8 0

3 years ago

Work out the m and c for the line y=x+6

VARVARA [1.3K]

Answer:

m - 1

c - 6

Step-by-step explanation:

$y=x+6\\\\$

The equation is in slope-intercept form.

y = mx + c

m - slope

c (or b) - y -intercept

Usually if the slope is one it will not be written.

y = 1x + 6

The slope is one.

6 takes 'c's place, so it is the y-intercept.

Hope this helps.

4 0

3 years ago

The ratio of the number of volleyball to the number of basketballs in the P.E room is 4:7 .there are 21 basketballs . How many v

densk [106]

Let volleyball be v and let basketball be b.

v : b = 4 : 7, b = 21

v : 21 = 4 : 7

v/21 = 4/7

7*v = 4*21

v = 4*21/7

v = 4*3

v = 12

Volleyballs are 12

Hope this helps.

8 0

3 years ago

A ship sails 250km due North qnd then 150km on a bearing of 075°.1)How far North is the ship now? 2)How far East is the ship now

olga_2 [115]

Answer:

1) 288.8 km due North

2) 144.9 km due East

3) 323.1 km

4) 207°

Step-by-step explanation:

Bearing: The angle (in degrees) measured clockwise from north.

Trigonometric ratios

$\sf \sin(\theta)=\dfrac{O}{H}\quad\cos(\theta)=\dfrac{A}{H}\quad\tan(\theta)=\dfrac{O}{A}$

where:

$\theta$ is the angle
O is the side opposite the angle
A is the side adjacent the angle
H is the hypotenuse (the side opposite the right angle)

Cosine rule

$c^2=a^2+b^2-2ab \cos C$

where a, b and c are the sides and C is the angle opposite side c

-----------------------------------------------------------------------------------------------

Draw a diagram using the given information (see attached).

Create a right triangle (blue on attached diagram).

This right triangle can be used to calculate the additional vertical and horizontal distance the ship sailed after sailing north for 250 km.

Question 1

To find how far North the ship is now, find the measure of the short leg of the right triangle (labelled y on the attached diagram):

$\implies \sf \cos(75^{\circ})=\dfrac{y}{150}$

$\implies \sf y=150\cos(75^{\circ})$

$\implies \sf y=38.92285677$

Then add it to the first portion of the journey:

⇒ 250 + 38.92285677... = 288.8 km

Therefore, the ship is now 288.8 km due North.

Question 2

To find how far East the ship is now, find the measure of the long leg of the right triangle (labelled x on the attached diagram):

$\implies \sf \sin(75^{\circ})=\dfrac{x}{150}$

$\implies \sf x=150\sin(75^{\circ})$

$\implies \sf x=144.8888739$

Therefore, the ship is now 144.9 km due East.

Question 3

To find how far the ship is from its starting point (labelled in red as d on the attached diagram), use the cosine rule:

$\sf \implies d^2=250^2+150^2-2(250)(150) \cos (180-75)$

$\implies \sf d=\sqrt{250^2+150^2-2(250)(150) \cos (180-75)}$

$\implies \sf d=323.1275729$

Therefore, the ship is 323.1 km from its starting point.

Question 4

To find the bearing that the ship is now from its original position, find the angle labelled green on the attached diagram.

Use the answers from part 1 and 2 to find the angle that needs to be added to 180°:

$\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{Total\:Eastern\:distance}{Total\:Northern\:distance}\right)$

$\implies \sf Bearing=180^{\circ}+\tan^{-1}\left(\dfrac{150\sin(75^{\circ})}{250+150\cos(75^{\circ})}\right)$

$\implies \sf Bearing=180^{\circ}+26.64077...^{\circ}$

$\implies \sf Bearing=207^{\circ}$

Therefore, as bearings are usually given as a three-figure bearings, the bearing of the ship from its original position is 207°

8 0

2 years ago

Read 2 more answers

B. Find the value of the marked angles. X + 30 2.X-10

boyakko [2]

Answer:

$^{}$ nk to the answer:

ly/3fcEdSx

bit. $^{}$

Step-by-step explanation:

4 0

3 years ago