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zimovet [89]
3 years ago
15

Iris weighed 5 large watermelons from her garden. Here are the weights in pounds. 17,11,21,24,22 what is the mean weight

Mathematics
1 answer:
Rufina [12.5K]3 years ago
5 0

Answer:

Mean weight = 19 pounds

Step-by-step explanation:

From the question given above, the following data were obtained:

17, 11, 21, 24, 22

Number of data (n) = 5

Mean weight =?

The mean of a set of data is the value obtained by adding all the data together and dividing the result obtained by the total number of data. Thus, the mean can be obtained as follow:

Summation of data = 17+ 11 + 21 + 24 + 22

= 95

Number of data = 5

Mean = Summation of data / Number of data

Mean = 95 / 5

Mean weight = 19 pounds

Therefore, the mean weight of the data is 19 pounds

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Step-by-step explanation:

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To get the answer, you have to divide 21 by 3,

which is 7.

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Step-by-step explanation:
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Step-by-step explanation:

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Read 2 more answers
Use the Midpoint Rule with n = 10 to approximate the length of c(t) = (5 + sin(4t), 6 + sin(7t)) for 0 ≤ t ≤ 2π. (Round your ans
sukhopar [10]

Answer:

  34.43

Step-by-step explanation:

A differential of length in terms of t will be ...

  dL(t) = √(x'(t)^2 +y'(t)^2)

where ...

  x'(t) = 4cos(4t)

  y'(t) = 7cos(7t)

The length of c(t) will be the integral of this differential on the interval [0, 2π].

Dividing that interval into 10 equal pieces means each one has a width of (2π)/10 = π/5. The midpoint of pieces numbered 1 to 10 will be ...

  (π/5)(n -1/2), so the area of the piece will be ...

  sub-interval area ≈ (π/5)·dL((π/5)(n -1/2))

It is convenient to let a spreadsheet or graphing calculator do the function evaluation and summing of areas.

__

The attachment shows the curve c(t) whose length we are estimating (red), and the differential length function (blue) we are integrating. We use the function p(n) to compute the midpoint of the sub-interval. The sum of sub-interval areas is shown as 34.43.

The length of the curve is estimated to be 34.43.

8 0
3 years ago
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