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3 years ago

Need contact number for this app!!!

Mathematics

2 answers:

gogolik [260]3 years ago

4 0

huh I don’t know but hope you find what your looking for

vovangra [49]3 years ago

3 0

Answer:

There is no number, I believe, but here:

brainly.com/app/contact

hope that helps!

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The question is asking to determine which statement is true?

Advocard [28]

Answer:

the answer is true which

7 0

2 years ago

Which expression is equivalent to sine startfraction 7 pi over 6 endfraction?

never [62]

The equivalent expression to the given one is -sin(pi/6).

<h3></h3><h3>Which expression is equivalent to the given one?</h3>

The given expression is:

sin(7pi/6)

Where the argument is in radians.

Remember that:

sin(a + b) = sin(a)*cos(b) + sin(b)*cos(a)

Now we can rewrite:

sin(7pi/6) = sin(pi + pi/6)

Then we can use the above relation to rewrite:

sin(pi + pi/6) = sin(pi)*cos( pi/6) + sin(pi/6)*cos(pi)

And we know that:

sin(pi) = 0

cos(pi) = -1

Then we can write:

sin(7pi/6) = - sin(pi/6)

If you want to learn more about the sine function:

brainly.com/question/9565966

#SPJ4

3 0

2 years ago

Which of the following figure is impossible to draw?

Fynjy0 [20]

D.)

When you say a equalterial triangle all sides have to be equal. In this case. 60,60,60 is a equilateral if it’s a obtuse this would be false.

4 0

2 years ago

Christopher earned $78 at his job when he worked for 2 hours.

morpeh [17]

Answer:

1 dollar every 1/39 hour

Step-by-step explanation:

If Christopher earns $78 in two hours, he must earn $39 dollars in one hour because 78/2 is 39. Therefore, every hour Christopher earns $39. To find the amount of hours per dollar, divide 1, the hour, by 39, the money per hour, to get 1/39.

4 0

3 years ago

Read 2 more answers

ASAP!!! Use the pythagorean theorem to prove that the point (√2/2, √2/2) lies on the unit circle. I need setup, explination, ans

docker41 [41]

Answer:

In brief, apply the pythagorean theorem to show that the distance between the point $(\sqrt{2}/2,\sqrt{2}/2)$ and the origin is $1$ .

Step-by-step explanation:

The pythagorean theorem can give the distance between two points on a plane if their coordinates are known.

A point is on a circle if its distance from the center of the circle is the same as the radius of the circle.

On a cartesian plane, the unit circle is a circle

centered at the origin $(0,0)$
with radius $1$ .

Therefore, to show that the point $(\sqrt{2}/2,\sqrt{2}/2)$ is on the unit circle, show that the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and $(0,0)$ equals to $1$ .

What's the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and $(0,0)$ ?

$\displaystyle \sqrt{\left(\frac{\sqrt{2}}{2}-0}\right)^{2} + \left(\frac{\sqrt{2}}{2}-0\right)^{2}} = \sqrt{\frac{1}{2} + \frac{1}{2}}= \sqrt{1}= 1$ .

By the pythagorean theorem, the distance between $(\sqrt{2}/2,\sqrt{2}/2)$ and the center of the unit circle, $(0,0)$ , is the same as the radius of the unit circle, $1$ . As a result, the point $(\sqrt{2}/2,\sqrt{2}/2)$ is on the unit circle.

3 0

3 years ago