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Illusion [34]
3 years ago
14

A cell phone provider offers a plan that costs $40 per month plus $0.10 per text message sent or received. A comparable plan cos

ts $70 per month but offers unlimited text messaging. How many text messages would have to be sent or received in order for the plans to cost the same each month? And if you send or receive an average of 100 text messages each month, which plan would you choose? Why?
Mathematics
1 answer:
anyanavicka [17]3 years ago
7 0
It would be 300 text message for the plan to cost the same each month
Mark as brainly
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Lynda cuts a piece of wood for a project. The first cut is shown and can be represented by the equation y=1/4x-5.The secend cut
Svetradugi [14.3K]

Since the second line is parallel to the first, it will have the same slope. The y-intercept of the new line is 4 (because of the coordinates given) so the equation of Lynda's second cut is y = 1/4x + 4 which is choice C

4 0
3 years ago
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What is the equation of the absolute function shown in the graph?
oee [108]

Answer is <u>6|x+2|+2</u>

Please check the attached image of answer to clear the doubt.

<em>By </em><em>Benjemin</em><em> </em>☺️

6 0
2 years ago
Can someone help me with this question?<br> 16 + (c + 17) = (16 + c) + 17
Furkat [3]

Answer:

c=∞

Step-by-step explanation:

Well first step we can add 16+17 on both sides

33+c=33+c

-33      -33

c=c

The answer is infinity

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2 years ago
A machine is designed to fill 16-ounce bottles of shampoo. When the machine is working properly, the amount poured into the bott
DiKsa [7]

Answer:

Between 15.95 ounces and 16.15 ounces.

Step-by-step explanation:

We have the following value m, being the mean, sd, being the standard deviation and n, the sample size:

m = 16.05

sd = 0.1005

n = 4

We apply the formula of this case, which would be:

m + - 2 * sd / (n ^ 1/2)

In this way we create a range, replacing we have:

16.05 + 2 * 0.1005 / (4 ^ 1/2) = 16.1505

16.05 - 2 * 0.1005 / (4 ^ 1/2) = 15.9495

Which means that 95% of all samples are between 15.95 ounces and 16.15 ounces.

4 0
3 years ago
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
laiz [17]

Answer:

Step-by-step explanation:

(A) The difference between an ordinary differential equation and an initial value problem is that an initial value problem is a differential equation which has condition(s) for optimization, such as a given value of the function at some point in the domain.

(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

M(t)Y"(t) + N(t)Y'(t) + O(t)Y(t) = K(t)

The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
3 years ago
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