Question

A circle is centered at the point (-3, 2) and passes through the point (1, 5). The radius of the circle is

Answer 1

Answer:

$r =5$

Step-by-step explanation:

Given

$(h,k) = (-3,2)$ -- center

$(x,y) = (1,5)$ --- pass through

Required

The radius (r)

The equation of circle is:

$(x - h)^2 + (y - k)^2 = r^2$

So, we have:

$(1 - -3)^2 + (5 - 2)^2 = r^2$

$(4)^2 + (3)^2 = r^2$

$16+9 = r^2$

$25 = r^2$

Take square roots of both sides

$5 = r$

$r =5$