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const2013 [10]
4 years ago
6

The width of the triangle is 3/4 the length. The perimeter is 252cm. What is the width of the triangle.

Mathematics
1 answer:
ICE Princess25 [194]4 years ago
7 0

Answer:

C).  54 cm.

Step-by-step explanation:

I think you mean a rectangle .

If the length is x then the width = 0.75x   (because 3/4 = 0.75).

Perimeter = 2*length + 2*width.

252 =  2x + 2*0.75x

252 = 2x + 1.5x

252 = 3.5x

x = 252 / 3.5

= 72  which is the length,

The width = 3/4 * 72

= 54 cm.

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21 minutes

Step-by-step explanation:

you first have to find how many words she writes in one minute. you do this by dividing 180/3=60. after that divide 1260 by 60 = 21 minutes.

4 0
3 years ago
Can someone explain how 8.75 multiplied by 0.8 is 7??? It just don't make sense... I don't see why the number got smaller instea
yarga [219]

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80% of 8.75=7. I'm pretty sure this is the reason.

3 0
3 years ago
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I'm having trouble on the problem...Will someone please give me step by step?
Reptile [31]

Answer:

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Step-by-step explanation:

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4 years ago
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Solve the system using elimination. 5x = –25 + 5y 10y = 42 + 2x
Serga [27]
<span>5x = –25 + 5y ---> 5x - 5y = -25 (1)
10y = 42 + 2x </span>---> 2x - 10y = -42 (2)
divide equation (2) by 2
so
x - 5y = -21

now you have
5x - 5y = -25
x - 5y = -21
-----------------subtract
4x = -4
  x = -1

substitute x = -1 into 5x - 5y = -25
5x - 5y = -25
5(-1) - 5y = -25
-5 - 5y = -25
-5y = -20
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answer
(-1 , 4)

3 0
4 years ago
I need a written answer for all three questions please.
Setler79 [48]

The values of the trigonometry ratios are:

  • cos α = - 5/13 and cot α = 5/12
  • cot α = -5/12 and sec α = 13/5

<h3>How to solve the trigonometry ratios?</h3>

<u>1: sin α = -12/13 and tan α > 0, find cos α and cot α</u>

Because tan α > 0, then it means that cos α and sin α are negative

So, we have:

sin²α + cos²α = 1

Substitute sin α = -12/13

(-12/13)² + cos²α = 1

This gives

cos²α = 1 - (-12/13)²

Evaluate the squares

cos²α = 1 - 144/169

Evaluate the difference

cos²α = 25/169

Take the square root of both sides

cos α = - 5/13

The cotangent ratio is represented as:

cot α = cos α/sin α

This gives

cot α = (-5/13)/(-12/13)

Evaluate

cot α = 5/12

Hence, cos α = - 5/13 and cot α = 5/12

<u>2: tan α = -12/5 for α in quadrant IV, find sec α and cot α</u>

Because α is in quadrant IV, then it means that sec α is positive

cot α = 1/tan α

This gives

cot α = 1/(-12/5)

Evaluate

cot α = -5/12

Also, we have:

sec²α = 1 + tan²α

Substitute tan α = -12/5

sec²α = 1 + (-12/5)²

Evaluate the squares

sec²α = 1 + 144/25

Evaluate the sum

sec²α = 169/25

Take the square root of both sides

sec α = 13/5

Hence, cot α = -5/12 and sec α = 13/5

Read more about trigonometry ratios at:

brainly.com/question/11967894

#SPJ1

5 0
2 years ago
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