<span>Cone Lateral Area = (<span>π<span> • r •<span> slant height)
</span></span></span></span><span>Cone Lateral Area = (PI * 3 * 5)
</span>Cone Lateral Area =
<span>
<span>
<span>
47.1
</span>
</span>
</span>
square inches
Cone Lateral Area =
<span>
<span>
47</span></span> square inches (rounded to nearest whole number).
Answer:
Angle CAD is 44 degrees
Angle ACD is 44 degrees
Angle ACB is 136 degrees
Angle ABC is 22 degrees
Explanation:
29. Triangle ADC is an isosceles triangle because it has two equal sides.
If segments AD and DC are congruent, then segment AC is the base and the base angles of an isosceles triangle are equal.
Let x be angle CAD.
Let's go ahead x;

Therefore, measure of angle CAD is 44 degrees.
30. Measure of angle ACD is 44 degrees (Base angles of an isosceles triangle are equal)
31. Let angle ACB be y,
Let's go ahead and find measure of angle ACB;

So measure of angle ACB is 136 degrees.
32. Let angle ABC be z.
Triangle ACB is also an isosceles triangle so the base angles are the same.
Let's go ahead and find z;

So measure of angle ABC is 22 degrees.
Answer:
1 pair of boots and 6 sweaters
Step-by-step explanation:
70+20s = 135
-70 -70
20s = 135
divide 20 both sides
s = 6.75
She can buy 6 sweaters because she cannot buy half a sweater.
s - sweaters
I need brainliest please
Answer:
A.The mean would increase.
Step-by-step explanation:
Outliers are numerical values in a data set that are very different from the other values. These values are either too large or too small compared to the others.
Presence of outliers effect the measures of central tendency.
The measures of central tendency are mean, median and mode.
The mean of a data set is a a single numerical value that describes the data set. The median is a numerical values that is the mid-value of the data set. The mode of a data set is the value with the highest frequency.
Effect of outliers on mean, median and mode:
- Mean: If the outlier is a very large value then the mean of the data increases and if it is a small value then the mean decreases.
- Median: The presence of outliers in a data set has a very mild effect on the median of the data.
- Mode: The presence of outliers does not have any effect on the mode.
The mean of the test scores without the outlier is:

*Here <em>n</em> is the number of observations.
So, with the outlier the mean is 86 and without the outlier the mean is 86.9333.
The mean increased.
Since the median cannot be computed without the actual data, no conclusion can be drawn about the median.
Conclusion:
After removing the outlier value of 72 the mean of the test scores increased from 86 to 86.9333.
Thus, the the truer statement will be that when the outlier is removed the mean of the data set increases.