How to graph y=-8/3x+9
2 answers:
Step-by-step explanation:
this is the equation for a line in slope-intercept form
the y-intercept is 9, so find (0,9) on the graph
then, the slope is -8/3 (think "rise" over "run"), so from the point (0,9) you have to count down 8 (for -8) and then to the right 3 (for +3). from this point, you can now repeat the pattern of counting down 8 and right 3 and making points to connect.
when at least two points are connected, you have a line and that is your graph
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Yee
(apologies in advance for foematring. I'm on mobile)
log rules
if no base is stared assume base 10
log_a(b)=c means a^c=b
log(a)+log(b)=log(ab)
if a^b=c^b and b=b then a=c
so
log(2x)+log(x)=2
log_10(2x^2)=2
10^2=2x^2
100=2x^
50=x^2
(apologies in advance for foematring. I'm on mobile)
log rules
if no base is stared assume base 10
log_a(b)=c means a^c=b
log(a)+log(b)=log(ab)
if a^b=c^b and b=b then a=c
so
log(2x)+log(x)=2
log_10(2x^2)=2
10^2=2x^2
100=2x^
50=x^2