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PIT_PIT [208]
3 years ago
12

A recipe for pie dough calls for a ratio of butter to flour of 4/5 : 3 1/3 . If you plan to use 6 2/3 cups of flour, how much bu

tter should you use to keep the same ratio?
Mathematics
1 answer:
erma4kov [3.2K]3 years ago
6 0

Answer:

1 3/5

Step-by-step explanation:

to determine the answer, take the following steps :

  1. determine how much larger the amount of flour you intend to use is more than that indicated in the recipe
  2. Multiply the answer gotten in the above step by the amount of flower indicated in the recipe

6 2/3 ÷ 3 1/3

20/3  x 3/10 = 2

2 x 4/5 = 8/5 = 1 3/5

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(3/5, -5) with undefined slope
soldier1979 [14.2K]

Answer:

x=3/5

Step-by-step explanation:

Since its undefined, the equation will use an x variable because all points on the line have (3/5,y).

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Please help me with this question!
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3 years ago
A bank offers all savings accounts 5% interest compounded annually. If one account has a principal of $100 and another
arsen [322]

Answer:

From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days .

Step-by-step explanation:

Given as :

The principal for the first account = p = $100

The rate of interest = r = 5% compounded annually

The account gets double , so, Amount = A = $200

Let the time after which account gets double = t years

So<u>, From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

As amount is double its principal

So, A = 2 × $100 = $200

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

Or, $200 = $100 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{200}{100} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

<u>Again </u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

As amount is double its principal

So, A = 2 × $1000 = $2000

Or, $2000 = $1000 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{2000}{1000} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

Hence From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days . Answer

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Choose the Athat seems to be congruent to the given one.<br> ΔABD=Δ
BaLLatris [955]

Answer:

Triangle AEC

Step-by-step explanation:

Triangle ABD seems to be congruent to triangle AEC, because AD looks like it's equal to AC, AB looks like it's equal to AE, and BD looks like it's equal to EC, satisfying the criteria for an SSS congruence. Of course you could also go by the angles for SAS, SAS or AAS.

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