3 years ago

HELP QUICKLY what is the equation of the line through (-10,-7) and (-5,-9)

Mathematics

2 answers:

hichkok12 [17]3 years ago

7 0

This is your answer

xenn [34]3 years ago

5 0

Answer:

$\frac{x + 10}{ - 5} = \frac{y + 7}{2}$

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A room is 12 m long and 8 m wide and 10 m high, find the area of the room.

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Find the slope between the points (−3,−5) and (10,-5)

balandron [24]

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Step-by-step explanation:

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ABDF is a regular hexagon. What is the measure of angle A?

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3 years ago

Find the inverse Laplace transform f(t) of the function F(s). Write uc for the Heaviside function that turns on at c, not uc(t).

zzz [600]

Answer:

F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

Step-by-step explanation:

We have given $F(S)=\frac{7e^{-7s}}{s^2-49}$

Now $F(S)=e^{-7s}G(s)$

Here $G(S)=\frac{7}{S^2-49}$

Now first find the Laplace inverse of G(S)

Using partial fraction

$\frac{7}{(s+7)(s-7)}=\frac{A}{(S+7)}+\frac{B}{S-7}$

$7=A(S-7)+B(S+7)$

On comparing the coefficient

$A=\frac{1}{2}$ and $B=\frac{-1}{2}$

On putting the value of A and B

$G(S)=\frac{-1}{2(S+7)}+\frac{1}{2(S+7)}$

Taking inverse Laplace

$G(t)=\frac{-1}{2}e^{7t}+\frac{1}{2}e^{-7t}$

Now in G(s) there is onether term $e^{-7s}$

So F(t) $=\frac{-1}{2}e^{7(t-7)}+\frac{1}{2}e^{-7(t-7)}$

6 0

3 years ago