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2 years ago

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Mathematics

1 answer:

Charra [1.4K]2 years ago

8 0

Answer:

annhbhhnnnnnnbhhhbbbbbbbbbbbbbbbbbbbbbbbnbnnnnnnnnnnnnnnnnnnnnnn 24cm2

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7(4x - 2) - 4(2x - 8)

vesna_86 [32]

Answer:

20x + 18

Step-by-step explanation:

We need to use the distributive property, where we essentially take the sum of the product of the outside number with each of the inside terms.

In 7(4x - 2), 7 is the outside number and 4x and -2 are the inside numbers, so:

7(4x - 2) = 7 * 4x + 7 * (-2) = 28x - 14

In 4(2x - 8), 4 is the outside number and 2x and -8 are the inside numbers, so:

4(2x - 8) = 4 * 2x + 4 * (-8) = 8x - 32

Now, we have:

28x - 14 - (8x - 32) = 28x - 14 - 8x + 32 = 20x + 18

The answer is 20x + 18.

6 0

2 years ago

Read 2 more answers

The surface area of a right circular cone of radius r and height h is S = πr√ r 2 + h 2 , and its volume is V = 1 3 πr2h. What i

kirill115 [55]

Answer:

Required largest volume is 0.407114 unit.

Step-by-step explanation:

Given surface area of a right circular cone of radious r and height h is,

$S=\pi r\sqrt{r^2+h^2}$

and volume,

$V=\frac{1}{3}\pi r^2 h$

To find the largest volume if the surface area is S=8 (say), then applying Lagranges multipliers,

$f(r,h)=\frac{1}{3}\pi r^2 h$

subject to,

$g(r,h)=\pi r\sqrt{r^2+h^2}=8\hfill (1)$

We know for maximum volume $r\neq 0$ . So let $\lambda$ be the Lagranges multipliers be such that,

$f_r=\lambda g_r$

$\implies \frac{2}{3}\pi r h=\lambda (\pi \sqrt{r^2+h^2}+\frac{\pi r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}r h= \lambda (\sqrt{r^2+h^2}+\frac{ r^2}{\sqrt{r^2+h^2}})\hfill (2)$

And,

$f_h=\lambda g_h$

$\implies \frac{1}{3}\pi r^2=\lambda \frac{\pi rh}{\sqrt{r^2+h^2}}$

$\implies \lambda=\frac{r\sqrt{r^2+h^2}}{3h}\hfill (3)$

Substitute (3) in (2) we get,

$\frac{2}{3}rh=\frac{r\sqrt{R^2+h^2}}{3h}(\sqrt{R^2+h^2+}+\frac{r^2}{\sqrt{r^2+h^2}})$

$\implies \frac{2}{3}rh=\frac{r}{3h}(2r^2+h^2)$

$\implies h^2=2r^2$

Substitute this value in (1) we get,

$\pi r\sqrt{h^2+r^2}=8$

$\implies \pi r \sqrt{2r^2+r^2}=8$

$\implies r=\sqrt{\frac{8}{\pi\sqrt{3}}}\equiv 1.21252$

Then,

$h=\sqrt{2}(1.21252)\equiv 1.71476$

Hence largest volume,

$V=\frac{1}{3}\times \pi \times\frac{\pi}{8\sqrt{3}}\times 1.71476=0.407114$

3 0

2 years ago

Find the zeros of f(x) = 7x² + 42.

goblinko [34]

Answer:

0,42

that should be the answer

7 0

2 years ago

Pls Help ASAP..................

AlekseyPX

Answer:

1. 8+(30/(2+4)) = 8+(30/6) = 8+5 = 13

2. ((8+30)/2)+4 = (38/2)+4 = 19+4 = 23

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

Ms. Pacheco, Mr Edwards, and Mr Richards are three math teachers at turner middle school. Ms. Pacheco is three years older than

zubka84 [21]

Mr edwards = Mr r x 2
Mr r = Mr p - 3 = Mr e ÷ 2. Mr p = 30
Mr e + Mr r = 81. Mr e = 54
Mr p = Mr r + 3. Mr r = 27

Mr Edwards = 2(Mr p - 3)
Mr e = 2(mr p) - 6

Mr r = [2(Mr p) -6] ÷ 2
Mr r = [2( Mr r + 3) - 6] ÷ 2

2(Mr r) + (Mr p - 3) = 81
2(Mr p -3) + (Mr p - 3) = 81
3(Mr p - 3) = 81
3(Mr p) - 9 = 81. Hope this helps!!!
3(Mr p) + 9 = 81 + 9
3(Mr p) = 90
Mr p = 90 ÷ 3
Mr p = 30

5 0

3 years ago

Read 2 more answers