Answer:
᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌ ᠌
A (n + y) = 10y + 32
(an + ay) = 10y + 32
an + ay = 32 + 10y
Solve for "a"
-32 + an + ay + (-10y) = 32 + 10y + (-32) + (-10y)
-32 + an + ay + -10y = 32 + -32 + 10y + -10y
<span>- 32 + an + ay + (-10y) = 0 + 10y + (-10y)
- 32 + an + ay + (-10y) = 10y + (-10y)
</span><span>10y + -10y = 0
-32 + an + ay + (-10y) = 0
Thi could not be determined. (no solution)</span>
Answer:
The equation for regression line and predicting a husband's height for married couples in their early 20s
Equation: Y'=33.67+0.54*X'
Step-by-step explanation:
r=0.5
x'=64.5
Sx=2.5
y'=68.5
Sy=2.7
General regression line equation is:
Y'=a+b*X'
so the slope of the regression line is the linear correlation coefficient multiplied by the standard deviation for y' divided by the standard deviation for x'

The intercept with axis y is the mean of the decreased by the product of the slope and the mean of x

The equation regression line then is:
Y'=33.67+0.54*X'