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kari74 [83]
3 years ago
5

Joe Bob wanted to find out how many hours of exercise the students at his school gets each week. He went to the school's gym and

asked the following question:
"Do you work out every day like a healthy person, or are you a lazy couch potato who only works out once in a while?"

What is another way Joe Bob could word his question so that it does not contain any bias?
Mathematics
1 answer:
gayaneshka [121]3 years ago
4 0

Although I am unsure what this question has to do with Mathematics, Joe Bob could simply say "How often do you work out in a week?"

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Tomas reparte 9 kg de mandarinas en mallas de tres cuartos de kilo cada una . ¿Cuantas mallas obtiene?
MrRissso [65]

Responder:

12

Explicación paso a paso:

Dado que:

Kilogramo total de mandarina = 9 kg

Tamaño de cada distribución = 3/4 de kilo

Número de mallas:

Kilogramo / tamaño total por distribución

9 kg ÷ 3/4 kg

9 * 4/3

= (9 * 4) / 3

= 36/3

= 12

7 0
2 years ago
Y = f(x) + 3<br> describe the functions that take place
hram777 [196]

Answer:

A function can be reflected about an axis by multiplying by negative one. To reflect about the y-axis, multiply every x by -1 to get -x. To reflect about the x-axis, multiply f(x) by -1 to get -f(x).

Step-by-step explanation:

8 0
3 years ago
Suppose you have a right triangle with congruent legs and a hypotenuse that measure (12sqrt(5))/5 What is the length of the smal
anastassius [24]

The length of the smaller leg is 3.79

<h3>How to determine the length of the smaller leg?</h3>

Represent the smaller leg with x.

So, we have:

x^2 + x^2 = ((12\sqrt5)/5)^2 -- Pythagoras theorem

This gives

2x^2 = 144/5

Divide by 2

x^2 = 72/5

This gives

x^2 = 14.4

Take the square root

x = 3.79

Hence, the length of the smaller leg is 3.79

Read more about right triangles at

brainly.com/question/6322314

#SPJ1

4 0
2 years ago
The longest side of the right triangle is 2 feet more than the middle side and the middle side is 1 foot less than twice the sho
Ket [755]
A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
3 0
3 years ago
58 = 7/4x well, basically I am really bad with fractions, and I'm supposed to do this on a computer, I don't have a calculator I
KiRa [710]
58=7/4x
Multiply both sides by 4 so the fraction cancels out:
232=7x
Divide both sides by 7:
x=33.14 (rounded)

Hope this helps :)
4 0
3 years ago
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