Answer:
a) 0.0082
b) 0.9987
c) 0.9192
d) 0.5000
e) 1
Step-by-step explanation:
The question is concerned with the mean of a sample.
From the central limit theorem we have the formula:

a) 
The area to the left of z=2.40 is 0.9918
The area to the right of z=2.40 is 1-0.9918=0.0082

b) 
The area to the left of z=3.00 is 0.9987

c) The z-value of 1200 is 0
The area to the left of 0 is 0.5

The area to the left of z=1.40 is 0.9192
The probability that the sample mean is between 1200 and 1214 is

d) From c) the probability that the sample mean will be greater than 1200 is 1-0.5000=0.5000
e) 
The area to the left of z=-112.65 is 0.
The area to the right of z=-112.65 is 1-0=1
I am assuming the 32 cases contain the small cans...
32 cases...with 28 small cans of fruit in each case..
32 * 28 = 896 small cans of fruit in total
24 cases...with 13 large cans of fruit in each case...
24 * 13 = 312 large cans of fruit in total
so there are (896 - 312) = 584 more small cans then large cans <==
Answer:2.84
Step-by-step explanation: 4.5% of 63.20
The first fraction is 7/10.
The second bag has the same probability as the top so just copy the fractions into the boxes.
To calculate the probability of the same colour being chosen you follow these steps.
P(RR) = 3/10 x 4/9 = 12/90
P(GG) = 7/10 x 5/9 = 35/90
Then add the two fractions.
12/90 + 35/90 = 47/90
The last box is 47/90.