Ask question

Ask question

All categories

mihalych1998 [28]

3 years ago

10

M is the midpoint of AB. A is at (-5, 1) and M is (-1,4). Find the coordinates of B. Select one: O a (-3.2.5) O b.(-1.4) O c. (2

,5) O d.(3,7)

1 answer:

coldgirl [10]3 years ago

4 0

Answer:

A (-3, 2.5)

Step-by-step explanation:

Midpoint formula is m=(x1 + x2/2), (y1 + y2/2)

So add the xs: -5 + -1 = -6

And the ys: 1 + 4 = 5

Then divide them by 2

(-3, 2.5)

You might be interested in

HELP PLEASE!! thanks

Vesna [10]

Answer:

352

but for the 3 it would be 264

5 0

3 years ago

The first two terms of the perfect square trinomial are given, find "c".

Naddik [55]

Answer:

A.) 36

Step-by-step explanation:

For a perfect square trinomial, a = 1 b = 2x c = x². For an example, (x+3)² = x² + 6x + 9.

For this trinomial, divide "b" by 2 to get 6. Square this number and you will have 36.

x² + 12x + 36

7 0

3 years ago

Read 2 more answers

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

7 0

2 years ago

HELP!!!! Find the area. Simplify your answer.<br> 552-9s<br> 3t2+t

Tems11 [23]

Answer:

A = (5s^2t - 9st) (3t + 1)

Step-by-step explanation:

(5s^2 - 9s) (3t^2 + t)

= 15s2t^2 + 5s^2t - 27st^2 - 9st

= 5s2t (3t + 1) - 9st (3t + 1)

= ( 5s^2t - 9st) (3t+1)

6 0

2 years ago

1/2 of 24? Please helpppppppop

Brut [27]

Answer:

Half of 24 is 12

Step-by-step explanation:

24/2 = 12

6 0

3 years ago

Read 2 more answers