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fiasKO [112]
3 years ago
6

If the farm has 5,000 spinach plants, describe a method that would produce a random sample of 10 plants.

Mathematics
2 answers:
jolli1 [7]3 years ago
7 0
Not sure if this is right but an example of a method to produce a random sample of 10 plants could be to sample 1 plant after every 500 plants.
Marina CMI [18]3 years ago
3 0
The answer is 5,000000 and 090
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Answer: B)

Step-by-step explanation: 21, 22, 22, 24, 24, 26, 26, 28, 29, 30, 32

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Answer:

D) All three have the same correlation coefficient.

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4 years ago
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What is the next term in the arithmetic sequence? 9,17,25,33,...
lions [1.4K]

<u>Answer:</u>

<u><em>41</em></u>

<u />

<u>Explanation:</u>

To solve this problem we must first understand what the pattern is in the arithmetic sequence. Once we understand the pattern, we can then apply it to the final known term to find the next term.

Take a look at the arithmetic sequence given:

<em>9, 17, 25, 33,...</em>

<em />

Let's start by figuring out how they got the second term in the sequence. To do that, subtract the second term by the first term. This will reveal the pattern.

<em>9 - first term</em>

<em>17 - second term</em>

<em />

<em>17 - 9 = 8</em>

<em />

So, this means they added eight to get the next term. Therefore, the pattern should be 'add eight' to get the next term. Just to be sure the pattern we found is correct, apply it to the given arithmetic sequence.

<em>9, 17, 25, 33,...</em>

<em>9 </em><em>+ 8 = </em><em>17</em>

<em>17  </em><em>+ 8 = </em><em>25</em>

<em>25 </em><em>+ 8 = </em><em>33</em>

<em />

So, since 'adding eight' every time gives us the next term, the pattern is correct.

Finally, let's continue the pattern to find the next term.

<em>9, 17, 25, 33,...</em>

<em />

<em>33 </em><em>+ 8 = </em><em>41</em>

<em />

<em>9, 17, 25, 33, 41,...</em>

<em />

Therefore, the next term in the arithmetic sequence is <u><em>41</em></u>.

3 0
3 years ago
Can someoneee please help me
icang [17]

9514 1404 393

Answer:

  37°

Step-by-step explanation:

The diagonals of a rhombus are angle bisectors. Angle 1 matches the other half of angle L.

  ∠1 = 37°

__

Angle 2 is the complement, 53°, and angle 3 is the same as angle 2, 53°.

The diagonals of a rhombus are perpendicular bisectors of each other, so angle 4 is 90°.

7 0
3 years ago
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