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stealth61 [152]
3 years ago
13

Given the right triangle, write the following trig ratios for cosecant, secant and cotangent. (20 points)

Mathematics
1 answer:
snow_tiger [21]3 years ago
7 0
Okay uhhh wait m figuring it out
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Nikkis charges are 20,40,50,80. Dave’s charges are 25 and 37.5.
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On sunday 1/16 of the people who visited for senior citizens, 3/16 or infants, 3/8 were children, and 3/8 for adults. How many o
Trava [24]
1/16=1,003, so

senior= 1003
infants=3009
children=6018
adults=6018
3 0
2 years ago
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Pam ask you to help her with the catering for the funeral. you decide to use juice concentrate to serve as a refreshing drink. t
ikadub [295]

Answer:

6.25 litres

Step-by-step explanation:

ratio 1:4

25/4 = 6.25

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Please help me with this homework
Sergio039 [100]
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5 0
2 years ago
Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
erica [24]
At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\
A=I(1 - r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &1013\\
I=\textit{initial amount}\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &0\\
p=period\to &1000
\end{cases}
\\\\\\
1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\
A=I(1- r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1013\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &t\\
p=period\to &1000
\end{cases}
\\\\\\
A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


7 0
3 years ago
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