Given the right triangle, write the following trig ratios for cosecant, secant and cotangent. (20 points)

If you want at least 3 pounds of hamburgers, then $6 is enough to buy those 3 pounds of hamburgers. If you ONLY buy 3 Pounds, then you also have enough for 4 pounds of chicken. $3 a pound x 4 = $12. You have 2 dollars left to spare, which means you can buy another pound of hamburgers. So 4 pounds each are able to be purchased.

4 0

3 years ago

How would I go about solving this problem???

schepotkina [342]

So.. if you take a peek at the picture below

the trunk is really just a half-cylinder on top of a square, with a depth of 2 meters

what's the volume? well, easy enough, take the volume of the cylinder, then half it
take the volume of the rectangular prism, and then add them both

$\bf \textit{volume of a cylinder}\\\\

\begin{array}{llll}
C=\pi r^2 h\\\\
\textit{half that}\\\\
\cfrac{\pi r^2 h}{2}
\end{array}\qquad 
\begin{cases}
r=radius\\
h=height\\
-------\\
r=\frac{1}{2}\\
h=2
\end{cases}\implies \cfrac{C}{2}=\cfrac{\pi \left( \frac{1}{2}\right)^2 2}{2}\\\\
-----------------------------\\\\
\textit{volume of a square}\\\\
V=lwh\qquad 
\begin{cases}
l=length\\
w=width\\
h=height
----------\\
l=1\\
w=1\\
h=2
\end{cases}\implies V=2$

now.. for the surface area... $\bf \textit{surface area of a cylinder}\\\\
\begin{array}{llll}
S=2\pi r(h+r)\\\\
\textit{half that}\\\\
\cfrac{2\pi r(h+r)}{2}
\end{array}\begin{cases}
r=radius\\
h=height\\
-------\\
r=\frac{1}{2}\\
h=2
\end{cases}$

now.. for the surface area of the prism... well

is really just 6 rectangles stacked up to each other at the edges

so... get the area of the lateral rectangles, and the one at the bottom, skip the rectangle atop, because is the one overlapping the cylinder, and is not outside, and thus is not surface area then

for the lateral ones, you have a front of 1x1, a back of 1x1 and a left of 1x2 and a right of 1x2, and then the one at the bottom, which is a 1x2

then add both surface areas, and that's the surface area of the trunk

5 0

3 years ago

1) You are designing a new kiddie soccer arena. The area of the rectangular

nikdorinn [45]

Answer:

The length of the rectangular field is 12 ft and the width is 5 ft.

Step-by-step explanation:

The area of a rectangle is:

$\text{Area} = \text{length}\times \text{width}$

The area of a rectangular field is, <em>A</em> = 60 ft.

The length of the field is:

l = w + 7

Compute the width of the field as follows:

$\text{Area} = \text{length}\times \text{width}$

$60=(w+7)\times w\\\\60=w^{2}+7w\\\\w^{2}+7w-60=0\\$

Factorize the last equation by splitting the middle term as follows:

$w^{2}+7w-60=0\\w^{2}+12w-5w-60=0\\w(w+12)-5(w+12)=0\\(w-5)(w+12)=0$

Now, since the width of rectangular field cannot be negative, the width is 5 ft.

Compute the length as follows:

l = w + 7

= 5 + 7

= 12

The length of the rectangular field is 12 ft.

7 0

3 years ago