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Ray Of Light [21]
3 years ago
7

If you were to heat up a 1-kilogram rock and 1 kilogram of water, you would see that the rock both gains heat and loses heat fas

ter than the water. If you allow them to cool down, which one will come back to room temperature faster?
Chemistry
1 answer:
Alex787 [66]3 years ago
6 0

Answer: If you were to heat up a 1-kilogram rock and 1 kilogram of water and allow them to cool down, you would notice that the rock returns to room temperature much faster than the water

Explanation:

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If 500.0 ml of 0.10 m ca2+ is mixed with 500.0 ml of 0.10 m so42−, what mass of calcium sulfate will precipitate? ksp for caso4
attashe74 [19]

Answer : The mass of calcium sulfate precipitate will be, 6.12 grams

Solution :

First we have to calculate the moles of Ca^{2+} and SO_4^{2-}.

\text{Moles of }Ca^{2+}=\text{Molarity of }Ca^{2+}\times \text{Volume of }Ca^{2+}=0.10mole/L\times 0.5L=0.05\text{ moles}

\text{Moles of }SO_4^{2-}=\text{Molarity of }SO_4^{2-}\times \text{Volume of }SO_4^{2-}=0.10mole/L\times 0.5L=0.05\text{ moles}

As, 0.05 moles of Ca^{2+} is mixed with 0.05 moles of  SO_4^{2-}, it gives 0.05 moles of calcium sulfate.

Now we have to calculate the solubility of calcium sulfate.

The balanced equilibrium reaction will be,

CaSO_4\rightleftharpoons Ca^{2+}+SO_4^{2-}

The expression for solubility constant for this reaction will be,

K_{sp}=(s)\times (s)

K_{sp}=(s)^2

Now put the value of K_{sp} in this expression, we get the solubility of calcium sulfate.

2.40\times 10^{-5}=(s)^2

s=4.89\times 10^{-3}M

Now we have to calculate the moles of dissolved calcium sulfate in one liter solution.

\text{Moles of }CaSO_4=\text{Molarity of }CaSO_4\times \text{Volume of }CaSO_4=4.89\times 10^{-3}mole/L\times 1L=4.89\times 10^{-3}\text{ moles}

Now we have to calculate the moles of calcium sulfate that precipitated.

\text{Moles of }CaSO_4\text{ precipitated}=\text{Moles of }CaSO_4\text{ present}-\text{Moles of }CaSO_4\text{ dissolved}

\text{Moles of }CaSO_4\text{ precipitated}=0.05-4.89\times 10^{-3}=0.045\text{ moles}

Now we have to calculate the mass of calcium sulfate that precipitated.

\text{Mass of }CaSO_4\text{ precipitated}=\text{Moles of }CaSO_4\text{ precipitated}\times \text{Molar mass of }CaSO_4

\text{Mass of }CaSO_4\text{ precipitated}=0.045moles\times 136g/mole=6.12g

Therefore, the mass of calcium sulfate precipitate will be, 6.12 grams

5 0
3 years ago
Read 2 more answers
Please help I will reward brainly THERE ARE 3 ANSWERS
elena-s [515]
ATP is formed

NADH releases electrons

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8 0
3 years ago
Read 2 more answers
A chemistry student is given 250.0 mL of clear aqueous solution at 42 C. He is told an unknown amount of a certain compound X is
lara [203]

Answer:

No

Explanation:

The solubility of a solid in water refers to the amount of that solid that dissolves in water.

It is not possible to calculate the solubility of the solid because the student threw away the first precipitate that formed. We already have the volume of water, but having lost some mass of precipitate, it has become impossible to accurately determine the solubility.

Hence the answer provided above.

7 0
3 years ago
235
lisov135 [29]

Answer:

Average atomic mass of uranium = 237.97 amu

Explanation:

Given data:

Abundance of U-234 = 0.01%

Abundance of U-235 = 0.71%

Abundance of U-238 = 99.28%

Average atomic mass of uranium = ?

Solution:

Average atomic mass  = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) + (abundance of 3rd isotope × its atomic mass)  / 100

Average atomic mass  = (234×0.01)+(235×0.71)+(238+99.28) /100

Average atomic mass =  2.34 + 166.85+23628.64 / 100

Average atomic mass = 23797.83 / 100

Average atomic mass = 237.97 amu.

3 0
3 years ago
There are two cups of water. The cups of water must have the same average Kinetic energy if they have the same ___
Oxana [17]

Answer:

Temperature and Heat

Explanation:

Proportional to the average kinetic energy of the molecules in a substance.

6 0
3 years ago
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