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shtirl [24]
4 years ago
15

A certain main-group element exhibits the following successive ionization energies in kJ/mol:IE1 = 100; IE2 = 2200; IE3 = 3300;

IE4 = 4100; IE5 = 5200Select the false statement about this element below.A) This is likely a Group 1A elementB) If this element is given a symbol "J", it would form an ionic compound with oxygen such as J2OC) This element is typically found as a free element rather than in compoundsD) If this element was in period 3 of the period table, it would be sodium E) This element is a metal
Chemistry
1 answer:
Alex787 [66]4 years ago
7 0

Answer:

The option C is the false statement

Explanation:

Ionization energy is the energy needed to completely pull out an electron from the valence electron of a gaseous atom.

The given values of ionization energy (kJmol⁻) for a main group element is: IE₁ = 100; IE₂ = 2200; IE₃ = 3300; IE₄ = 4100; IE₅ = 5200

Since<u> first ionization energy is very low</u> and the <u>difference between the first and the second ionization energy</u> for the given element is <u>very high</u>.

Therefore, <u>the given chemical element is most likely an alkali metal</u> belonging to the<u> group IA of the periodic table.</u>

As the alkali metals react with oxygen to form oxides. So, the given <u>element (J</u>) can react with oxygen to form <u>oxide of the formula J₂O</u>.

Since the given element has <u>low first ionization energy, thus it is reactive</u>. Therefore, the given element <u>can not exist as a free element.</u>

If the given chemical element belongs to <u>the period 3</u> of the periodic table, then it is should be the group IA alkali metal,<u> sodium</u>.

<u>Therefore, option C is the false statement.</u>

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