Answer:
6
Step-by-step explanation:
Prime factorization of 18 = 2 × 3 × 3
Prime factorization of 24 = 2 × 2 × 2 × 3
Common factors of 18 and 24 = 2 × 3 = 6
HCF (18,24) = 6
Answer: A number used to describe a set of values with a single number
Step-by-step explanation:
Answer:
3, 15, 14
Step-by-step explanation:
x + 5x + ( 5x -1) = 32
11x - 1 = 32
11x = 32 + 1
11x = 33
11x/11 = 33/11
x = 3
therefore
the first number is 3
the second is 5 × 3 = 15
the third number is 15 - 1 = 14
Answer:
The area of the shaded portion of the figure is
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The shaded area is equal to the area of the square less the area not shaded.
There are 4 "not shaded" regions.
step 1
Find the area of square ABCD
The area of square is equal to
![A=b^2](https://tex.z-dn.net/?f=A%3Db%5E2)
where
b is the length side of the square
we have
![b=4\ cm](https://tex.z-dn.net/?f=b%3D4%5C%20cm)
substitute
![A=4^2=16\ cm^2](https://tex.z-dn.net/?f=A%3D4%5E2%3D16%5C%20cm%5E2)
step 2
We can find the area of 2 "not shaded" regions by calculating the area of the square less two semi-circles (one circle):
The area of circle is equal to
![A=\pi r^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E%7B2%7D)
The diameter of the circle is equal to the length side of the square
so
---> radius is half the diameter
substitute
![A=\pi (2)^{2}](https://tex.z-dn.net/?f=A%3D%5Cpi%20%282%29%5E%7B2%7D)
![A=4\pi\ cm^2](https://tex.z-dn.net/?f=A%3D4%5Cpi%5C%20cm%5E2)
Therefore, the area of 2 "not-shaded" regions is:
![A=(16-4\pi) \ cm^2](https://tex.z-dn.net/?f=A%3D%2816-4%5Cpi%29%20%5C%20cm%5E2)
and the area of 4 "not-shaded" regions is:
![A=2(16-4\pi)=(32-8\pi)\ cm^2](https://tex.z-dn.net/?f=A%3D2%2816-4%5Cpi%29%3D%2832-8%5Cpi%29%5C%20cm%5E2)
step 3
Find the area of the shaded region
Remember that the area of the shaded region is the area of the square less 4 "not shaded" regions:
so
---> exact value
assume
![\pi =3.14](https://tex.z-dn.net/?f=%5Cpi%20%3D3.14)
substitute