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sattari [20]
2 years ago
14

A bag contains 1 gold marbles, 6 silver marbles, and 29 black marbles. Someone offers to play this game: You randomly select one

marble from the bag. If it is gold, you win $4. If it is silver, you win $2. If it is black, you lose $1. What is your expected value if you play this game?
Mathematics
2 answers:
pentagon [3]2 years ago
7 0

Answer:

the expected value is -$1

algol [13]2 years ago
4 0

Answer:

7$ it is

Step-by-step explanation:

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If the perimeter of an isosceles triangle is
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6 cm for both sides

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A girl cut off 2/5 of a ribbon. The piece she cut off was 5 meters long.How
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12.5

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5/2*5=12.5

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Caleb throws a ball three times for his dog Leo. For each throw, Leo either
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Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.
Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0
2 years ago
110 + 3x +11 = 16x + 4 solve for x
sashaice [31]

Answer:

x = 9

Step-by-step explanation:

110 + 3x + 11 = 16x + 4

121 + 3x = 16x + 4

<u>        -3x    -3x</u>

121 = 13x + 4

<u>-4             - 4</u>

117 = 13x

117 ÷ 13 = x

9 = x

Check:

110 + 3(9) + 11 = 16(9) + 4

121 + 27 = 144 + 4

148 = 148

6 0
2 years ago
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