Answer:
BElabora un esquema y resuelve el problema.
Step-by-step explanation:
you need to know the mass of the jewelry box before you can know the volume but i can help you multiply th 15 and the 10 to get the mass most likely then divided what you have from 15 x 10 by the depth and you have your answer just be sure to round it off!
Sadly, after giving all the necessary data, you forgot to ask the question.
Here are some general considerations that jump out when we play with
that data:
<em>For the first object:</em>
The object's weight is (mass) x (gravity) = 2 x 9.8 = 19.6 newtons
The force needed to lift it at a steady speed is 19.6 newtons.
The potential energy it gains every time it rises 1 meter is 19.6 joules.
If it's rising at 2 meters per second, then it's gaining 39.2 joules of
potential energy per second.
The machine that's lifting it is providing 39.2 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(2)(4) = 4 joules.
<em>For the second object:</em>
The object's weight is (mass) x (gravity) = 4 x 9.8 = 39.2 newtons
The force needed to lift it at a steady speed is 39.2 newtons.
The potential energy it gains every time it rises 1 meter is 39.2 joules.
If it's rising at 3 meters per second, then it's gaining 117.6 joules of
potential energy per second.
The machine that's lifting it is providing 117.6 watts of lifting power.
The object's kinetic energy is 1/2 (mass) (speed)² = 1/2(4)(9) = 18 joules.
If you go back and find out what the question is, there's a good chance that
you might find the answer here, or something that can lead you to it.
Answer:
The garden is 9 feet wide and 26 feet long.
Step-by-step explanation:
L = W+17
area = LW = 234
(W+17)W = 234
W²+17W-234 = 0
Quadratic formula
W = [-17 ± √(17² – 4·1(-234))] / [2·1]
= [-17 ± √1225] / 2
= [-17 ± 35] /2
= -26, 9
-26 is an extraneous solution
W = 9
L = W+17 = 26
The garden is 9 feet wide and 26 feet long.
Answer:
There were 76 childrens and 14 adults.
Step-by-step explanation:
Since the group has a total of 90 children and adults, then the sum of the number of adults with the number of children must be equal to 90 as shown below:
children + adults = 90
Since the total cost for their tickets was 548 then the number of children multiplied by the price of their ticket summed by the number of adults multiplied by the price of their ticket must be equal to that. We have:
5*children + 12*adults = 548
With these two equations we have a system of equations shown below:
children + adults = 90
5*children + 12*adults = 548
In order to solve this we will multiply the first equation by -5, and sum both equations we have:
-5*children - 5*adults = -450
5*children + 12*adults = 548
7*adults = 98
adults = 98/7 = 14
children + 14 = 90
children = 90 - 14 = 76
There were 76 childrens and 14 adults.
