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3 years ago

Which of the following is the correct factorization of the polynomial below?

Mathematics

1 answer:

VladimirAG [237]3 years ago

8 0

Answer:

Step-by-step explanation:

The polynomial cannot be factored with rational numbers.

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Pls help me and show working

Juliette [100K]

Answer:

4x + 10 > 3x + 14

x > 4

Step-by-step explanation:

Use the given values for length and width in the formula for perimeter of a rectangle. You will be able to find the perimeter of rectangles A and B.

A = 2(l + w)

A = 2(x + 5 + x)

A = 2(2x + 5)

A = 4x + 10

B = 2(l + w)

B = 2(x + 7 + x/2)

B = 2(3x/2 + 7)

B = 3x + 14

The perimeter of rectangle A is larger than that of rectangle B.

A > B

4x + 10 > 3x + 14

(4x + 10) - 3x > (3x + 14) - 3x

x + 10 > 14

(x + 10) - 10 > 14 - 10

x > 4

6 0

3 years ago

Suppose you needed to subtract a from b but mistakenly subtract b from a instead. How is the answer you get related to the corre

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3 years ago

n order to bring back customers to the AMC Movie Theaters, they are offering two movie plans; a Family Plan of 4 used to cost $2

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3 years ago

Read 2 more answers

You earn 50,000 per year,and paid 10 percent in taxes this year. the government increased the tax rate to 20 percent foe the nex

bulgar [2K]

Answer:

Step-by-step explanation:

he paid 5000 in taxes last year multiply by 2 10000

D is the answer sorry i dont have a proper explanation

4 0

3 years ago

Hamburger Hut sells regular hamburgers as well as a larger burger. Either type can include cheese, relish, lettuce, tomato, must

Studentka2010 [4]

Answer:

a) 40 different hamburgers can be ordered with exactly three extras

b) 20 different regular hamburgers can be ordered with exactly three extras

c) 7 different regular hamburgers can be ordered with at least five extras

Step-by-step explanation:

The order in which the extras are ordered is not important. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this problem:

2 options of hamburger(regular or larger)

6 options of extras(cheese, relish, lettuce, tomato, mustard, or catsup.).

(a) How many different hamburgers can be ordered with exactly three extras?

1 hamburger type, from a set of 2.

3 extras, from a set of 6. So

$C_{2,1}*C_{6,3} = \frac{2!}{1!(2-1)!}*\frac{6!}{3!(6-3)!} = 2*20 = 40$

40 different hamburgers can be ordered with exactly three extras

(b) How many different regular hamburgers can be ordered with exactly three extras?

3 extras, from a set of 6. So

$C_{6,3} = \frac{6!}{3!(6-3)!} = 20$

20 different regular hamburgers can be ordered with exactly three extras

(c) How many different regular hamburgers can be ordered with at least five extras?

Five extras:

5 extras, from a set of 6. So

$C_{6,5} = \frac{6!}{5!(6-5)!} = 6$

Six extras:

6 extras, from a set of 6. So

$C_{6,6} = \frac{6!}{6!(6-6)!} = 1$

6 + 1 = 7

7 different regular hamburgers can be ordered with at least five extras

8 0

3 years ago