BD=90 DF=110 meaning BF=200
200/5x
X=40
Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
Answer:
Step-by-step explanatio11n:
116
Answer:
19,14
Step-by-step explanation:
x=5+y
x+ y= 33
we will solve using substitution
(5+y) +y= 33
5+y+y=33
5+2y=33
subtract 5 from both sides
2y=28
y=14
We got y now we will find what x is
for this, we will substitute y's value (14) into the first equation
x=5+(14)
x=19
we got x too
