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Nata [24]
3 years ago
7

What is 6x^2-2x+1=0 plz help

Mathematics
1 answer:
Kazeer [188]3 years ago
4 0
6x^2 - 2x + 1 is a quadratic formula from the form ax^2 + bx + c. This form of equation represents a parabola.
Finding 6x^2 - 2x + 1 = 0, means that you need to find the zeroes of the equation.
Δ = b^2 - 4ac
If Δ>0, the equation admits 2 zeroes and 6x^2 - 2x + 1 = 0 exists for 2 values of x.
If Δ<0, the equation doesn't admit any zero, and 6x^2 - 2x + 1 = 0 doesn't exist since the parabola doesn't intersect with the axe X'X
If Δ=0, the equation admits 1 zero, which means that the peak of the parabola is touching the axe X'X.

In 6x^2 - 2x + 1, a=6, b=-2, and c =1.
Δ= b^2 - 4ac
Δ=(-2)^2 - 4(6)(1)
Δ= 4 - 24
Δ= -20
Δ<0 so the parabola doesn't intersect with the Axe X'X, which means there's no solution for 6x^2 - 2x + 1 = 0.

I've added a picture of the parabola represented by this equation under the answer.

Hope this Helps! :)

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I really need help on both but if you can only answer one that's perfectly fine!
Fofino [41]

Answer:

110, 15%

Step-by-step explanation:

So for the first problem, recall that there is 100%. 12% of the answers on a test were missed.

There are 125 questions on the test.

To find the answer, what we can do it multiply 125 by 100%-12%

So 125*88%

THis can be looked at as:

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So we know the first answer is 110, now lets move onto the next one.

There a few ways of diong this, we could do 100%- each of the answers, and then multiply that by 2760 and see if we get 2400, but there is an easier way of doign this.

Take your 2760, and divide it by 2400. This will get you 1.15. So 2400 is increases by .15. This is equal to an increase of 15%.

There is a catch to this one however, when you divide 2400 by 2760, which should get you 85%, it gets you 86%. This would be 14%. So the answer seems to be 15%, but if not, its none of the above.

So answers:

110 and 15%(or none of the above)

Hope this helps! I am sorry about the bottom answer though, but 15% makes the most sense to me.

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Only the last paragrph is needed.

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