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3 years ago

Solve the logarthmic equation. 2 log3(x + 4) - log39 = 2

Mathematics

1 answer:

Genrish500 [490]3 years ago

3 0

Answer:

Step-by-step explanation:

2 log₃(x + 4) − log₃9 = 2

2 log₃(x + 4) − log₃3² = 2

2 log₃(x + 4) − 2 = 2

2 log₃(x + 4) = 4

log₃(x + 4) = 2

3^(log₃(x + 4)) = 3^2

x + 4 = 9

x = 5

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Write an equation in point-slope form of the line that passes through the point (5, 1) and has a slope of -3

bogdanovich [222]

Answer:

Step-by-step explanation:

An equation in point-slope form of the line that passes through the point (x₁,y₁) and has a slope of m:

y - y₁ = m(x - x₁)

m = -3

(5, 1) ⇒ x₁ = 5, y₁ = 1

Therefore:

y - 1 = -3(x - 5)

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3 years ago

16 + 32 ÷ 4 + (10 - 6)2

fenix001 [56]

Answer:

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Read 2 more answers

Alicia can row 6 miles downstream in the same time it takes her to row 4 miles upstream.She rows downstream miles/hour faster th

disa [49]

Answer:

Option D. 9 mi/hr downstream, 6 mi/hr upstream

Step-by-step explanation:

The complete question is

Alicia can row 6 miles downstream in the same time it takes her to row 4 miles upstream. She rows downstream 3 miles/hour faster than she rows upstream. Find Alicia’s rowing rate each way

Define the variables

Let

x -----> Alicia's rowing rate downstream in miles per hour

y ----> Alicia's rowing rate upstream in miles per hour

we know that

The rate is equal to the distance divided by the time

The time is equal to the distance divided by the rate

we have

$\frac{6}{x}=\frac{4}{y}$

$4x=6y$

$x=1.5y$ -----> equation A

$x=y+3$ ----> equation B

equate equation A and equation B

$1.5y=y+3$

$1.5y-y=3$

$0.5y=3$

$y=6$

Find the value of x

$x=1.5(6)=9$

therefore

Alicia's rowing rate downstream is 9 mi/h

Alicia's rowing rate upstream is 6 mi/h

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4 years ago

How do I remove the 1 on the numerator when solving for x 1/x = 5

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Answer:

x = $\frac{1}{5}$

Step-by-step explanation:

$\frac{1}{x}$ = 5 ( multiply both sides by x to clear the fraction )

1 = 5x ( divide both sides by 5 )

$\frac{1}{5}$ = x

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