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luda_lava [24]
3 years ago
13

Solve the logarthmic equation. 2 log3(x + 4) - log39 = 2

Mathematics
1 answer:
Genrish500 [490]3 years ago
3 0

Answer:

5

Step-by-step explanation:

2 log₃(x + 4) − log₃9 = 2

2 log₃(x + 4) − log₃3² = 2

2 log₃(x + 4) − 2 = 2

2 log₃(x + 4) = 4

log₃(x + 4) = 2

3^(log₃(x + 4)) = 3^2

x + 4 = 9

x = 5

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7 students have 8 books each. Which helps you find the total number of books?
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7 × 8

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What is (f-g)(x)?<br><br> question equation show in picture
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4 years ago
This problem addresses some common algebraic errors. For the equalities stated below assume that x and y stand for real numbers.
weqwewe [10]

Answer:

The answers are:

a) (x+y)^2 = x^2 + y^2 is FALSE.

b) (x+y)^2 = x^2 + 2xy + y^2 is TRUE.

c) \frac{x}{x+y}= \frac{1}{y} is FALSE.

d) x-(x+y) = y is FALSE.

e) \sqrt{x^2} = x is FALSE.

f) \sqrt{x^2} = |x| is TRUE.

g) \sqrt{x^2+4} = x+2 is FALSE.

h) \frac{1}{x+y} = \frac{1}{x} + \frac{1}{y} is FALSE.

Step-by-step explanation:

We can show that the FALSE statement are, in fact, false finding an example where the equality fails.

a) Take x=2 and y=3 and notice that (2+3)² = 25, while 2²+3²=4+9=13.

b) (x+y)² = (x+y)(x+y)=x²+xy+xy+y² = x² +2xy +y².

c) Take x=2 and y=3 and notice that 2/(2+3) = 2/5 which is different from 1/3.

d) Take x=2 and y=3 and notice that 2-(2+3) = 2-5=-3 which is different from 3. Recall that x-(x+y) = x-x-y=-y.

e) Take x=-2, and notice that [tax]\sqrt{(-2)^2} = \sqrt{4} = 2[/tex] which is different from -2.

f) The previous example illustrate why this is true.

g) Take x=1, and notice that sqrt{1^2+4} = \sqrt{5} which is different from 3.

h) Take x=2 and y=3 and notice that 1/(2+3)=1/5 and 1/3+1/2 = 5/6.

3 0
3 years ago
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