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SVEN [57.7K]
3 years ago
13

Solve 3x2 + 5 = -2x using the Quadratic Formula.

Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

x=−1−i√143,−1+i√143

Step-by-step explanation:

basically the answer for the two X'S IS 3

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True or false to find the percent of a number we convert to a fraction or a decimal and then divide the number
8_murik_8 [283]

true, when you convert to a decimal, you add a zero in the variable

4 0
3 years ago
At the bank, Sheila made 6 deposits, each in the same amount. Her sister Sherri made 5 deposits, each in the same amount. Each o
Serga [27]
<span /><span>TLDR: Equation is 5(10 + x) = 6x. x = 50, so Sheila deposited $50 each 6 trips. Sherri deposited $60 each 5 trips. Both of them deposited $300 in total.

</span>Sherri deposited $10 more into her bank account than Sheila each 5 times. Expression: 5(x + 10).

Sheila deposited money 6 times
Expression: (6)(x) or 6x

Put it all together and the equation is 5(x+10)=6x. 

Solve by distributing the 5 on the right side of the equation 5(x+10) to get 5x + 50 = 6x. Subtract 5x on both sides of equation. 5x - 5x + 50 = 6x - 5x to get 50 = 1x. Divide by 1 on each side to isolate the variable. x = 50. Sheila paid $50 in each of her 6 deposits, so she deposited $300 in total. Check the equation by replacing x with 50. 

Sherri paid $60 in each of her 5 deposits because 50 + 10 is 60. 60 by 5 is also $300. 


3 0
3 years ago
DUE TODAY ANSWER ASAP WILL MARK BRAINLIEST
Vilka [71]

Answer:

66

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
2<br>If A=<br>4 3<br>find A1 using<br>elementary row operations.​
MA_775_DIABLO [31]

Answer:   A^{-1}=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

<u>Step-by-step explanation:</u>

                  \left[\begin{array}{cc}2&1\\4&3\end{array}\right]=\left[\begin{array}{cc}1&0\\0&1\end{array}\right]

\dfrac{1}{2}Row\ 1\rightarrow\left[\begin{array}{cc}1&\frac{1}{2}\\4&3\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\0&1\end{array}\right]

Row\ 2 -4 \ Row\ 1\rightarrow \left[\begin{array}{cc}1&\frac{1}{2}\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{1}{2}&0\\-2&1\end{array}\right]

Row\ 1-\dfrac{1}{2}\ Row\ 2 \rightarrow \left[\begin{array}{cc}1&0\\0&1\end{array}\right]=\left[\begin{array}{cc}\frac{3}{2}&-\frac{1}{2}\\-2&1\end{array}\right]

5 0
3 years ago
Thank you in advance for those who provided support to my question!
alekssr [168]

GCF of 10 and 12 is 2

LCM of 16 and 24 is 48

Added together is 50

5 0
3 years ago
Read 2 more answers
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