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Bess [88]
3 years ago
11

Find an expression that is equivalent to this expression:

Mathematics
1 answer:
Ostrovityanka [42]3 years ago
6 0
There is not expression listed above. 
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Put these numbers in order from least to greatest.<br><br> 1/8,1/2,0.13, and 7/8
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Answer: 1/8, 0.13, 1/2, 7/8

Step-by-step explanation: Mental Math

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"Sam" and "Martha" are the local names for two lighthouses that guard a particularly dangerous part of the coast. Sam blinks eve
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Sam and Martha will blink again in 24 seconds :)

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During a sale, for each shirt that Mark purchased at the regular price, he also purchased a shirt at half the regular price. How
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3 years ago
The position of an object along a vertical line is given by s(t) = −t3 + 3t2 + 7t + 4, where s is measured in feet and t is meas
saw5 [17]

Answer:

The maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

Step-by-step explanation:

Given : The position of an object along a vertical line is given by s(t) = -t^3+3t^2+7t +4, where s is measured in feet and t is measured in seconds.

To find : What is the maximum velocity of the object in the time interval [0, 4]?

Solution :

The velocity is rate of change of distance w.r.t time.

Distance in terms of t is given by,

s(t) = -t^3+3t^2+7t +4

Derivate w.r.t. time,

v(t)=s'(t) = -3t^2+6t+7

It is a quadratic function so its maximum is at vertex of the function.

The x point of the function is given by,

x=-\frac{b}{2a}

Where, a=-3, b=6 and c=7

t=-\frac{6}{2(-3)}

t=-\frac{6}{-6}

t=1

As 1 lie between interval [0,4]

Substitute t=1 in the function,

v(t)= -3(1)^2+6(1)+7

v(t)= -3+6+7

v(1)=10

Th maximum velocity is 10 ft/s.

Therefore, the maximum velocity of the object in the time interval [0, 4] is 10 ft/s.

8 0
2 years ago
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Will mark as BRAINLIEST
Anon25 [30]

Answer:

B and E

Step-by-step explanation:

B. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 1 do not form right angles.

E. The quadrilaterals cannot be placed such that each occupies one-quarter of the circle because the vertices of parallelogram 4 do not form right angles.

Step-by-step explanation:

hope it helps:3

7 0
2 years ago
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