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alisha [4.7K]
3 years ago
7

A regular hexagon (6-sided figure) has sides that are all the same length. Each side length is represented by the expression x +

⅓ y. a) Write an algebraic expression that represents the perimeter of the hexagon. b) Use one of the expressions and evaluate the perimeter of the hexagon if x = 5 and y = 6 HELPPPPP!!!!!
Mathematics
1 answer:
Mandarinka [93]3 years ago
8 0
Perimiter=6 times legnth of one side
P=6(x+1/3y)
P=6x+6/3y
P=6x+2y

if x=5 and y=6
P=6(5)+2(6)
P=30+12
P=42


A. P=6x+2y
B. 42 units is the perimiter
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Quadrilateral ABCD is inscribed in a circle with angle measures m∠A = (11x − 8)°, m∠B = (3x2 + 1)°, m∠C = (15x + 32)°, and m∠D =
dimulka [17.4K]

Answer:

No for all of the 4 values

Step-by-step explanation:

The sum of the internal angles of a quadrilateral is always 360°, so we have that:

m∠A + m∠B + m∠C + m∠D = 360

11x - 8 + 3x2 + 1 + 15x + 32 + 2x2 - 1 = 360

5x2 + 26x - 320 = 0

Solving the quadratic function using Bhaskara's formula, we have:

Delta = 26^2 + 4*5*320 = 7076

sqrt(Delta) = 84.12

x1 = (-26 + 84.12)/10 = 5.81

x2 = (-26 - 84.12)/10 = -11.01 (this value will generate negative angles, so it is not valid).

Now, finding the angles, we have:

m∠A = 11*5.81 - 8 = 55.91°

m∠B = 3*(5.81)^2 + 1 = 102.27­°

m∠C = 15*5.81 + 32 = 119.15°

m∠D = 2*(5.81)^2 - 1 = 66.51°

As all these values are different from the values shown, the answer is No for all of them.

8 0
3 years ago
What is the sum of the interior angles of nonregular hexagons?
gavmur [86]

Answer:

They add up to 720 degrees

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ohaa [14]

The next term is -88.7

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3 years ago
Write 19/25 as a decimal and a percent
bixtya [17]

Answer:

19/25

Decimal: 0.76

Percent: 76%

Step-by-step explanation:

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3 years ago
the problem is kamala had 5,026 grams  flour in a canister.she brought a 4,158 gram bag of flour.she poured some flour from the
andrey2020 [161]
Hello, 

x= amount of flour that she poured in the canister

there was 5,026 grams of flour, and now: 5,026+x

In the bag there was 4,158, now: 4,158

I says that as a result the mass of the flour in the canister is twice the mass of the flour left in the bag, so:

5,026+x=2*(4,158-x) \\ 5,026+x=8,316-2x \\ 3x=8,316-5,026 \\ 3x=3,290 \\ x=1,096.67

So, she poured 1,096.67 grams, we subtract this from the initial amount in the bag and we have the answer:

4,158g-1,096.67=\boxed{3,061.33}

Answer: there is 3,061.33 grams of flour in the bag
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