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3 years ago

Yesterday the temperature at noon was 15.3°F. By midnight, it had gone down by 26°F. What was the temperature at midnight?

Mathematics

1 answer:

rusak2 [61]3 years ago

8 0

Answer:

-10.7°F.

<u>Steps used to get answer:</u>

1. Use this rule: a-b= -(b-a)

-(26-15.3)

2. Use the algorithm method.

5 10

26.0

- 15.3

---------------------

10.7

3. After simplification, we have:

−(26−15.3)=−10.7

4. Therefore, 15.3-26=-10.7

−10.7°F.

<u>Done by NeighborhoodDealer</u>

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<h3>Right triangles </h3>

Right triangles have a pair of perpendicular lines

Coordinates

The coordinates are given as:

D = (-2,-1)
E = (-2,2)
F = (0,0)

<h3>Slopes</h3>

Start by calculating the slopes of lines DF and EF using:

$m = \frac{y_2 -y_1}{x_2 -x_1}$

So, we have:

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Also, we have:

$m_{EF} = \frac{0 -2 }{0+2}$

$m_{EF} = \frac{-2 }{2}$

$m_{EF} = -1$

For the triangle to be a right triangle, then the calculated slopes must be opposite reciprocals.

i.e.

$m_1 = -\frac{1}{m_2}$

By comparison, the slopes of both lines are not opposite reciprocals.

Hence, the true statement is (c)

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V of cone=(1/3)(pi)(h)(r^2)
V of cylinder=(pi)(h)(r^2)

1.
r=6
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v=(1/3)(pi)(10)(6^2)
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v=1/3pi360
v=120pi
answer is B

2.
r=d/2
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3. 9.2, 3.7
V=(pi)(9.2)(3.7^2)
V=(pi)(9.2)(13.69)
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input 125.948

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