Answer:
The answer is below
Step-by-step explanation:
Let us assume the rate of printing in machine A is x per hour and the rate for machine B is y. Given that machine B prints at half the rate of machine A, therefore:
y = (1/2)x (1)
Also, both machine produces 200 newspaper printouts, and both operate at different times for a total of 4 hours. Therefore:
200/x + 200/y = 4 (2)
Put y = (1/2)x in equation:
Put x = 150 in equation y:
y=(1/2)150 = 75
Therefore the rate of machine A is 150 newspapers per hour while that of machine B is 75 newspapers per hour
