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3 years ago

5

How to do operations with exponents

1 answer:

Dennis_Churaev [7]3 years ago

4 0

What do you mean? In the order of operations exponents would be 2nd (pemdas) parentheses, exponents, multiplication,division, addition, subtraction

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Ten members of the academic team went to a local restaurant after their contest. Each meal combo that came with soda cost $6.75,

Aneli [31]

Answer:

7 ordered with Soda;

3 ordered with water

Step-by-step explanation:

Given

$m \to$ With water

$n \to$ With Soda

So:

$m + n =10$ --- total

$5m + 6.75n = 62.25$ -- cost

Required

Find m and n

$m + n =10$

Make m the subject

$m = 10 - n$

Substitute $m = 10 - n$ in $5m + 6.75n = 62.25$

$5(10-n) +6.75n = 62.25$

$50-5n +6.75n = 62.25$

Collect like terms

$-5n +6.75n = 62.25 - 50$

$-5n +6.75n = 12.25$

$1.75n = 12.25$

Solve for n

$n = 12.25/1.75$

$n = 7$

$m = 10 - n$

$m = 10 - 7$

$m =3$

8 0

3 years ago

The Monthly Bank pays 3 percent interest, compounded monthly, on their savings accounts. The Daily Bank pays 3 percent interest,

Novosadov [1.4K]

Answer:

The amount that we should deposit in each bank is around $942.

Step-by-step explanation:

Case 1:

A=$1000

n = 12

t = 2

r = 3% or 0.03

p = ?

The compound interest formula is :

$A=p(1+\frac{r}{n})^{nt}$

Substituting values in the formula;

$1000=p(1+\frac{0.03}{12})^{12\times2}$

=> $1000=p(1.0025)^{24}$

=> $1000=1.06175p$

$p=\frac{1000}{1.06175}$

p = $941.84

Case 2:

A=$1000

n = 365

t = 2

r = 3% or 0.03

p = ?

$1000=p(1+\frac{0.03}{365})^{365\times2}$

=> $1000=p(1.0000822)^{730}$

=> $1000=1.06184p$

$p=\frac{1000}{1.06184}$

p = $941.76

The amount that we should deposit in each bank is around $942.

5 0

3 years ago

Read 2 more answers

If f(x)=x³-2x²-73x-70, which of the following is not a factor of f(x)?

noname [10]

Answer:

C. (x + 10)

Step-by-step explanation:

3 0

3 years ago

Find the equation of a line given the point and slope below.

Levart [38]

Step-by-step explanation:

$\frac{y - 6}{x - 3} = - 3$

$- 3(x - 3) = y - 6$

$- 3x + 9 = y - 6$

$y = - 3x + 9 + 6 = - 3x + 15$

Option C

4 0

4 years ago

For what value of the constant c is the function fcontinuous on (−[infinity], [infinity])?

Arlecino [84]

Answer:

For $c=\frac{1}{7}$ the function f(x) is continuous on $(-\infty,\infty)$ .

Step-by-step explanation:

We have the following function

$f(x) = \left\{ \begin{array}{ll} cx^2+5x & \quad x$

For the function f(x) to be continuous on $(-\infty,\infty)$ it is sufficient to have continuity at x = 6, we need to ensure that as x approaches 6, the left and right limits match, this means that

$\lim_{x \to 6^{-} } f(x)=\lim_{x \to 6^{+} } f(x)=f(x)$ ,

which holds if and only if

$c\left(6\right)^2+5\left(6\right)=\left(6\right)^2-c\left(6\right)\\36c+30=36-6c\\42c=6$

namely if $c=\frac{1}{7}$ .

6 0

3 years ago