Answer:
y=-
x+
Step-by-step explanation:
First, calculate the slope of the line that is perpendicular to the equation of line we are asked to find
m=(y2-y1)/(x2-x1)
=(2-(-4))/(-2-1)
=6/-3
=-2
in this equation the slope is 2, and to find the first equation, use y=mx+b
use the point (1, -4) to find b
-4=(2)(1)+b
-4=2+b
b=-6
the first equation of the line is y=2x-6
to find the x intercept of that line substitute 0 for y
0=2x-6
2x=6
x=3
the slope of a line perpendicular to this would be the opposite reciprocal of the slope which would be equal to -1/2
for the second equation of the line to pass thorugh the x-intercept of the first line, it must pass through (3, 0), so substitute and solve for b
y=mx+b
0=(-1/2)(3)+b
b=3/2
thus the equation of the line that is perpendicular to the line through (1,-4) and (-2, 2) and passes through the x intercept of that line is y=-
x+3/2
Answer:
-10x+7.5
Step-by-step explanation:
-2.5(4x-3)
Multiply each term by -2.5
-2.5 * 4x = -10x
-2.5 * 3 = 7.5
-10x + 7.5
Its D............................
I think the answer would have to be complex
Answer:
R = 12
L = 84
Step-by-step explanation:
R + L =96
L = 7R
R = 1R
L = 7R
1 R + 7R = 8R
R = 12
L = 84
hope it helps,