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3 years ago

What is the value of y in the equation 4 + y = −3? (1 point) 7, 1, −1, −7

Mathematics

1 answer:

Marta_Voda [28]3 years ago

8 0

Hello!

$\large\boxed{y = -7}$

4 + y = -3

Isolate for y.

Subtract both sides by 4:

4 - 4 + y = -3 - 4

y = -7

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3 years ago

Read 2 more answers

Which is the equation of a hyperbola centered at the origin with x-intercept +\- 3 and asymptote y=2x

Radda [10]

Answer:

${\dfrac{x^{2}}{9} - \dfrac{y^{2}}{36} = 1}$

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The center is at (h,k).

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3. For 'b': The equation for the asymptote with the positive slope is

$y = k + \dfrac{b}{a}(x - h) = \dfrac{b}{a}x$

Thus, asymptote has the slope of

$\begin{array}{rcl}m& =& \dfrac{b}{a}\\\\2& =& \dfrac{b}{3}\\\\b& =& \mathbf{6}\end{array}$

4. The equation of the hyperbola is

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The attachment below represents your hyperbola with x-intercepts at ±3 and asymptotes with slope ±2.

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3 years ago

The functions r and s are defined as follows.

irina1246 [14]

Answer:

r(s(-2)) = -2

Step-by-step explanation:

We are given these following functions:

$r(x) = -2x + 2$

$s(x) = x^2 - 2$

Find the value of r(s (-2)).

First we find the composition of r and s functions. It is:

$r(s(x)) = r(x^2-2) = -2(x^2-2) + 2 = -2x^2 + 6$

At x = -2

$r(s(-2)) = -2(-2)^2 + 6 = -8 + 6 = -2$

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3 years ago