Please help timed test

Mathematics

1 answer:

Alexandra [31]2 years ago

3 0

Answer:

x=2x,3x,5x

Step-by-step explanation:

surface area of prism-6480 u3..

I don't know if I'm correct

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7. One serving of Ms. Scott's tomato soup is 0.75 cup. How many servings are in the 72-cup pot? 104.2. servings 10.42 servings 9

valina [46]

Answer:

96 Servings

Step-by-step explanation:

Divide the total 72 cups by the serving, 0.75 cup, which equals 96 servings

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2 years ago

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If z=3−5i, find |z|.

geniusboy [140]

Answer:

Step-by-step explanation:

The absolute value of z is the distance between the point graphed from the complex number and the origin on a complex plane. In a complex plane, the x axis is replaced by R, real numbers, and the y axis is replaced by i, the complex part of the complex number. Our real number is positive 3 and the complex number is -5, so we go to the right 3 and then down 5 and make a point. Connect that point to the origin and then connect the point to the x axis at 3 to construct a right triangle that has a base of 3 and a length of -5. To find the distance of the point to the origin is to find the length of the hypotenuse of that right triangle using Pythagorean's Theorem. Therefore:

$|z|=\sqrt{(3)^2+(-5)^2}$ and

$|z|=\sqrt{9+25}$ and

$|z|=\sqrt{34}$

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3 years ago

Express 5.412 hours to the nearest minute

Agata [3.3K]

Answer:323.72

Step-by-step explanation:

Begin by multiplying 60 by 5 hours.

Then 60 minutes by 0.412

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2 years ago

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Consider an urn containing 8 white balls, 7 red balls and 5 black balls.

weqwewe [10]

Answer + Step-by-step explanation:

1) The probability of getting 2 white balls is equal to:

$=\frac{8}{20} \times \frac{7}{19}\\\\= 0.147368421053$

2) the probability of getting 2 white balls is equal to:

$=C^{2}_{5}\times (\frac{8}{20} \times \frac{7}{19}) \times (\frac{12}{18} \times \frac{11}{17} \times \frac{10}{16})\\=0.397316821465$

3) The probability of getting at least 72 white balls is:

$=C^{72}_{150}\times \left( \frac{8}{20} \right)^{72} \times \left( \frac{7}{20} \right)^{78} +C^{73}_{150}\times \left( \frac{8}{20} \right)^{73} \times \left( \frac{7}{20} \right)^{77} + \cdots +C^{149}_{150}\times \left( \frac{8}{20} \right)^{149} \times \left( \frac{7}{20} \right)^{1} +\left( \frac{8}{20} \right)^{150}$