For the first point, remember this simple rule: every exponential function 
always returns 
when evaluated at 
. In fact, 
for every possible base .
So, we can see that the graph of the exponential passes through the point 
where 
appears to be between 1 and 2. So, the only feasible option would be 
, because it passes throught the point 
because 
.
The other functions are wrong because:
would pass through 
, which would be between 0 and 1 on the y axis
would pass through 
, which would be between 2 and 3 on the y axis
would pass through 
, which would be between 0 and 1 on the y axis
As for the second question, you simply have to plug in the values: the function
means that you have to choose an input, x, and use it as exponent for 7. So, if you choose x=2, it means that you have to give exponent 2 to 7, i.e. you replace the x with the specific value, 2.
So, the expression becomes
Answer:$10.52
Step-by-step explanation:
Answer:
12 gallons
Step-by-step explanation:
a)
well done
b)
well, a function for a relationship means, the x-coordinates must not repeat in a set, namely that for every "y" there must be a unique "x" coordinate, no X-REPEATS.
so for example in a relation that say is { (3, 4) , (5, 4) , (7, 4) , (10, 11) }, we do have y-coordinates repeated, but for a function that doesn't matter, our x-coordinates are not repeated thus, it's a function.
in this case, let's see the relationship set, just a few points { (3,5) , (3,6) , (3,8) , (6,10)}, well darn, we have 3 repeated three times in the x-coordinate slots, therefore is not a function, just a relation.
(-1.2,-2.0) and (1.9,2.2) are the best approximations of the solutions to this system.
Option B
<u>Step-by-step explanation:</u>
Here, we have a graph of two functions from which we need to find the approximate value of common solutions. Let's find this:
First look at where we have intersection points, In first quadrant & in third quadrant.
<u>At first quadrant:</u>
Draw perpendicular lines from x-axis & y-axis from this point . After doing this we can clearly see that the perpendicular lines cut x-axis at x=1.9 and y-axis at y=2.2. So, one point is (1.9,2.2)
<u>At Third quadrant:</u>
Draw perpendicular lines from x-axis & y-axis from this point. After doing this we can clearly see that the perpendicular lines cut x-axis at x=-1.2 and y-axis at y= -2.0. So, other point is (-1.2,-2.0).
