Answer:
Therefore the maximum number of video games that we can purchase
is 6.
Step-by-step explanation:
i) Let us say the number of video game system we can buy that costs $185
is x and the number of video games of cost $14.95 is y.
ii) The total amount we can spend on the purchase of the video game
system is $280.
iii) Now with the amount of $280 mentioned in ii) we can see that the
number of game systems that can be bought is 1.
Therefore x = 1.
Therefore the equation we can write to equate the number of video
games and video game system is given by $185 + $14.95 × y ≤ 280
Therefore 14.95 × y ≤ 280 - 185 = 95
Therefore y ≤ 95 ÷ 14.95 = 6.355
Therefore the maximum number of video games that we can purchase
is 6.
12 x 12 = 144
11 x 11 = 121
Sqrt130 between the two,
Answer:
Assumption
Let A be the event that the person stops at first signal.
Let B be the event that the person stops at second signal.
Given
Probabilities:
P(A)=0.40
P(B)=0.50
P(A∪B)=0.50
(a) Stops at both signals
The probability that person stops at both signals is intersection of events A and B
P(A∩B) = P(A)+P(B)−P(A∪B)
= 0.4+0.5−0.6=0.9−0.6
=0.3
(b) Stops at first but not at second
The given case is intersection of event A wth compliment of B
P(A∩¯B) = P(A)−P(A∩B)
=0.40−0.30
=0.10
(c) Stops at exactly one signal
The given case is sum of events that when a person stops either only first signal or at only second signal.
P = [P(A)−P(A∩B)]+[P(B)−P(A∩B)]
= [0.4−0.3]+[0.5−0.3]
= [0.1]+[0.2]
= 0.10+0.20
=0.30
Answer:What are the following?
Step-by-step explanation:
Answer:
334.65
Step-by-step explanation:
Multiply 5.75×33 and 3.45×42
then add them together to get 334.65