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Vaselesa [24]
2 years ago
7

You need 3 1/2 cups of flour for each batch of cupcakes. How many whole batches can make if you have 17 cups of flour? Show two

ways.
Mathematics
1 answer:
rosijanka [135]2 years ago
3 0

<u>ANSWER:</u>

4 batches of cupcakes can be made.

<u>SOLUTION: </u>

Given, we need 3\frac{1}{2} cups of flour for each batch of cupcakes. And we have 17 cups of flour.

We need to find how many batches can be made.

1st way:

We will get the number of batches when we divide the available cups with cups required for one batch.

Available cups = 17 and required cups for one batch = 3\frac{1}{2} = \frac{7}{2} cups

number of batches = $\frac{17}{\frac{7}{2}}$

$=\frac{17}{1} \times \frac{2}{7}$

$=\frac{34}{7}$ = 4.857

As the number of batches can’t be fraction, we will neglect the fractional part.

2nd way:

Let the number of batches be x.

Then, cups of flour required for batches must be less than available flour

(x)(\frac{7}{2}) < 17

(x)(7) < (2)(17)

7x < 34

x < \frac{34}{7}

x < 4.857

As the number of batches must be an whole number, x becomes 4.

Hence, 4 batches of cupcakes can be made.

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the difference between 2 whole number is 66 the ratio of the 2 whole number is 2.5 what are the two numbers​​
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Given :difference between 2 whole number = 66ratio of the 2 whole number =2:5Let:1 whole number be 2x2 whole number be 5xA/Q

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Let's turn it into algebraic equation:

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Now Let's put value of x to find two whole numbers

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The first side of a triangle is 3 inches shorter than the second side, and 2 inches longer than the third side. How long is each
ziro4ka [17]

Answer:

the length of the first side of the triangle is \frac{28}{3}\ in

the length of the second side of the triangle is \frac{37}{3}\ in

the length of the third side of the triangle is \frac{19}{3}\ in

Step-by-step explanation:

Let

x-----> the length of the first side of a triangle

y----> the length of the second side of a triangle

z---> the length of the third side of a triangle

we know that

x=y-3

y=x+3 -----> equation A

x=z+3

z=x-3  -----> equation B

The perimeter of the triangle is equal to

P=x+y+z

P=28\ in

so

28=x+y+z -----> equation C

substitute equation A and equation B in equation C

28=x+(x+3)+(x-3)

solve for x

28=3x

x=\frac{28}{3}\ in

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the first side of a triangle is x

x=\frac{28}{3}\ in

the second side of a triangle is y

y=\frac{28}{3}+3=\frac{37}{3}\ in

the third side of a triangle is z

z=\frac{28}{3}-3=\frac{19}{3}\ in

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