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Tom [10]
3 years ago
5

Please help me with this question

Mathematics
2 answers:
natali 33 [55]3 years ago
5 0
Your answer would be 9\frac{2}{3}
Delicious77 [7]3 years ago
5 0
20 flowers obvious its not 20
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Step-by-step explanation:

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What is 78.5 rounded to the nearest hundredth
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Which function is graphed below?? TIMED HELP
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6 0
3 years ago
A pair of shoes costs $70.00. How much will the customer pay after 7% sales tax is added to the purchase?
ANEK [815]

Answer:

$74.90

Step-by-step explanation:

If $70 is your original price, you would need to multiply it by 1.07, because that is 107%.

Since the original price is 100% of the price, and sales tax is another 7% of the price, you are multiplying the original price by 107%, again making $74.90.

Do you understand?

5 0
3 years ago
Use the appropriate substitutions to write down the first four nonzero terms of the Maclaurin series for the binomial (1+3x)^(-1
PolarNik [594]

Answer:

First term=1

Second term=-x

Third term=2x^2

Fourth term =-\frac{28}{3!}x^3

Step-by-step explanation:

We are given that function

f(x)=(1+3x)^{-1/3}

We have to find the  first four non zero terms of the Maclaurin series for the binomial.

Maclaurin series of function f(x) is given by

f(x)=f(0)+f'(0)x+\frac{1}{2!}f''(0)x^2+\frac{1}{3!}f'''(0)x^3+....

f(0)=(1+3x)^{\frac{-1}{3}}=1

f'(x)=-\frac{1}{3}(1+3x)^{-\frac{4}{3}}(3)=-(1+3x)^{-\frac{4}{3}}

f'(0)=-1

f''(x)=\frac{4}{3}\times 3 (1+3x)^{-\frac{7}{3}}

f''(0)=4

f'''(x)=-4\times \frac{7}{3}\times 3(1+3x)^{-\frac{10}{3}}

f'''(0)=-28

Substitute the values we get

(1+3x)^{-\frac{1}{3}}=1-x+\frac{4}{2!}x^2+\frac{-28}{3!}x^3+...

(1+3x)^{-\frac{1}{3}}=1-x+2x^2+\frac{-28}{3!}x^3+...

First term=1

Second term=-x

Third term=2x^2

Fourth term =-\frac{28}{3!}x^3

5 0
3 years ago
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