HURRY I NEED TO TURN IT IN SO I DONT GET AN REFERALL ALSO I NEED TWO ANSWERS

Mathematics

2 answers:

professor190 [17]3 years ago

6 0

Answer:

i think that one of the answers is (3,2)

Step-by-step explanation:

vekshin13 years ago

3 0

Answer:

Step-by-step explanation:

4,6

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PLEASE HELP!!! WILL GIVE BRANLIEST

Rus_ich [418]

Check the picture below, so the hyperbola looks more or less like that.

based on the provided vertices, its center is at the origin, as you see there, the "a" component or traverse axis is 4, the "c" distance is 5.

$\bf \textit{hyperbolas, vertical traverse axis }
\\\\
\cfrac{(y- k)^2}{ a^2}-\cfrac{(x- h)^2}{ b^2}=1
\qquad 
\begin{cases}
center\ ( h, k)\\
vertices\ ( h, k\pm a)\\
c=\textit{distance from}\\
\qquad \textit{center to foci}\\
\qquad \sqrt{ a ^2 + b ^2}
\end{cases}\\\\
-------------------------------$

$\bf \begin{cases}
h=0\\
k=0\\
c=5\\
a=4
\end{cases}\implies \cfrac{(y-0)^2}{4^2}-\cfrac{(x-0)^2}{b^2}=1
\\\\\\
\stackrel{c}{5}=\sqrt{4^2+b^2}\implies 5^2=16+b^2\implies 25=16+b^2
\\\\\\
9=b^2\implies \sqrt{9}=b\implies \boxed{3=b}
\\\\\\
\cfrac{(y-0)^2}{4^2}-\cfrac{(x-0)^2}{3^2}=1\implies \cfrac{y^2}{16}-\cfrac{x^2}{9}=1$

3 0

4 years ago

Read 2 more answers

If your bank charges an out-of-network service fee of $3.00, and you withdraw $20 from each of three out-of-network atms, how mu

earnstyle [38]

U get charged $ 3 for every out-of-network atm.....

u visited 3 out-of-network atm's....and in each one, u withdrew $ 20

3( 20 + 3) =
3(23) =
69 <=== so $ 69 will be removed from ur account

3 0

3 years ago

Read 2 more answers

Solve for y 2/x - 3/y = 1/z

love history [14]

Answer:

$\frac{2}{x} - \frac{3}{y} = \frac{1}{z} \\ \frac{2}{x} - \frac{1}{z} = \frac{3}{y} \\ y = \frac{3}{\frac{2}{x} - \frac{1}{z} } \\ y = \frac{3xz}{2z - x}$