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erastova [34]
3 years ago
15

Help pls!! If AB= 8, what is BD in square ABCD??

Mathematics
1 answer:
expeople1 [14]3 years ago
4 0

Answer:

option b

Step-by-step explanation:

sine all sides of a square are equal, AD = 8 too

therefore with pythagoras theorem,

AD^2 + AB^2 = BD^2

8^2 + 8^2 = BD^2

64 + 64 = BD^2

128 = BD^2

BD = root of 128 = 8 root 2 (b option)

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My calculator does not have a 3 key that works! How can I use this broken calculator to do 23 x 45.
erik [133]
<h3><u>Solution:-</u></h3>

\longrightarrow This problem can be tackled by using distributive property of multiplication .

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\green{ \underline { \boxed{ \sf{(a±b)\times c = a \times c±b\times c}}}}

<u>Similarly</u>,

\quad23 × 45

\longrightarrow(21+2) ×45

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It can also be done as-

\quad23 × 45

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2 years ago
What is 3/4- (-5 1/4) =<br><br> NEED HELP ASAP
Fantom [35]

Answer:

6

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\frac{3}{4} - (-\frac{21}{4})

negative and negative becomes positive

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Both fractions have same denominators. so we can combine the numerators

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3 years ago
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What is the vertex form of 2x^2+12x+14
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Answer:

2 (x + 3)^2 - 2

Step-by-step explanation:

1. Factor the 2 out of the equation (don't forget about it - it will be used later). This gives you x^2 + 6x + 7

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3. Take b (6), divide it by 2 (3), and square it (9). Then add that to both sides of the equation. This gives you x^2 + 6x + 9 = 2

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8 0
4 years ago
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