Answer:
option b
Step-by-step explanation:
sine all sides of a square are equal, AD = 8 too
therefore with pythagoras theorem,
AD^2 + AB^2 = BD^2
8^2 + 8^2 = BD^2
64 + 64 = BD^2
128 = BD^2
BD = root of 128 = 8 root 2 (b option)
The limit it converges to is 0
the answer is 1/10.....and yh
50
1+3+5+7+9+11+13+15+17+19= 100/2= 50
10
4+5=9 and 1/2+1/2 =1 so 9+1=10
