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Daniel [21]
3 years ago
15

In 2012, there were approximately 8,950 public libraries in the United States. A survey found that 76% of those libraries offere

d free access to electronic books. Based on this information, how many public libraries offered free access to electronic books in 2012?
Mathematics
2 answers:
yarga [219]3 years ago
8 0
The answer is 6,802.




Bess [88]3 years ago
4 0

Answer:

6,802

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago
Use the euclidean algorithm to find
kvasek [131]
A)
18=1\cdot12+6
12=2\cdot6+0
\implies\mathrm{gcd}(12,18)=6

b)
201=1\cdot111+90
111=1\cdot90+21
90=4\cdot21+6
21=3\cdot6+3
6=2\cdot3+0
\implies\mathrm{gcd}(111,201)=3

c)
1331=1\cdot1001+330
1001=3\cdot330+11
330=30\cdot11+0
\implies\mathrm{gcd}(1001,1331)=11

d)
54321=4\cdot12345+4941
12345=2\cdot4941+2463
4941=2\cdot2463+15
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15=5\cdot3+0
\implies\mathrm{gcd}(12345,54321)=3

e)
5040=5\cdot1000+40
1000=25\cdot40+0
\implies\mathrm{gcd}(1000,5040)=40

f)
9888=1\cdot6060+3828
6060=1\cdot3828+2232
3828=1\cdot2232+1596
2232=1\cdot1596+636
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8 0
3 years ago
On the basis of data collected during an experiment, a biologist found that the growth of a fruit fly population (Drosophila) wi
Ket [755]

Answer:

(a). 15

(b). 78

Step-by-step explanation:

Growth of the population of a fruit fly is modeled by

N(t) = \frac{600}{1+39e^{-0.16t} }

where t = number of days from the beginning of the experiment.

(a). For t = 0 [Initial population]

N(0) = \frac{600}{1+39e^{-0.16\times 0} }

       = \frac{600}{1+39}

       = \frac{600}{40}

       = 15

Initial population of the fruit flies were 15.

(b).Population of the fruit fly colony on 11th day.

N(11) = \frac{600}{1+39e^{-0.16\times 11} }

       = \frac{600}{1+39e^{-1.76} }

       = \frac{600}{1+39\times 0.172 }

       = \frac{600}{1+6.71}

       = \frac{600}{7.71}

       = 77.82

       ≈ 78

On 11th day number of fruit flies colony were 78.

3 0
3 years ago
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