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scZoUnD [109]
3 years ago
7

Identify the properties used in Step 1 and Step 2 to solve the equation shown. Then discuss why those properties were used. Prob

lem: Steps: 2x + 6 = 22 Given problem 2x = 16 (1) Identify and discuss the property that was used. x = 8 (2) Identify and discuss the property that was used.
Mathematics
2 answers:
noname [10]3 years ago
8 0

Answer:

can you make it more clear?

Step-by-step explanation:

Alex Ar [27]3 years ago
7 0
<h3>Step-by-step explanation:</h3>

<u>Step</u>                <u>Property</u>

2x+6 = 22       given

2x = 16            addition property of equality (-6 added to both sides)

x = 8                multiplication property of equality (both sides × 1/2)

_____

In general equations are solved by reversing the steps done to the variable. Here, the variable (x) is multiplied by 2 and 6 is added to that product. So, to find x, we undo the addition of 6 (by adding -6, the additive inverse), and undo the multiplication by 2 (by multiplying by 1/2, the multiplicative inverse).

If other functions were performed on the variable in the original equation, their inverse functions would be used, too, as part of the solution process.

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Given the equation Y -3 equals 1/2 (X +6 )in point slope form identify the equation of the same line in standard form
liberstina [14]

The standard form of a line:

Ax+By=C

We have the equation of a line in the slope-point form:

y-3=\dfrac{1}{2}(x+6)      use distributive property

y-3=\dfrac{1}{2}x+3       add 3 to both sides

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4 0
4 years ago
Jack looks at a clock tower from a distance and determines that the angle of elevation of the top of the tower is 40°. John, who
zmey [24]

Answer:

18.7939 m

Step-by-step explanation:

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#Taking the right triangle ACD:

\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 60\textdegree=\frac{y+1.5}{x}\\\\y=x \ Tan \ 60\textdegree -1.5

#Taking the right triangle ABD:

\Tan \ theta=\frac{Perpendicular \ Height}{Base}\\\\Tan \ 40\textdegree=\frac{y+1.5}{x+20}\\\\y=(x+20)\ Tan \ 40\textdegree -1.5

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(x+20)\ Tan \ 40\textdegree -1.5=x\ Tan \ 60\textdegree -1.5\\\\(x+20)\ Tan \ 40\textdegree=x\ Tan \ 60\textdegree\\\\0.8391x+16.7820=1.7321x\\\\x=18.7939

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8 0
3 years ago
1 + tanx / 1 + cotx =2
Lera25 [3.4K]

Answer:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

Step-by-step explanation:

Solve for x:

1 + cot(x) + tan(x) = 2

Multiply both sides of 1 + cot(x) + tan(x) = 2 by tan(x):

1 + tan(x) + tan^2(x) = 2 tan(x)

Subtract 2 tan(x) from both sides:

1 - tan(x) + tan^2(x) = 0

Subtract 1 from both sides:

tan^2(x) - tan(x) = -1

Add 1/4 to both sides:

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Write the left hand side as a square:

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Add 1/2 to both sides:

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Take the inverse tangent of both sides:

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or tan(x) - 1/2 = -(i sqrt(3))/2

Add 1/2 to both sides:

x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or tan(x) = 1/2 - (i sqrt(3))/2

Take the inverse tangent of both sides:

Answer:  x = tan^(-1)((i sqrt(3))/2 + 1/2) + π n_1 for n_1 element Z

or x = tan^(-1)(-(i sqrt(3))/2 + 1/2) + π n_2 for n_2 element Z

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