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3 years ago

Emilio's designs call Seven rectangles in every 140cm .How many rectangles will be presented in 220 cm

Mathematics

1 answer:

Likurg_2 [28]3 years ago

3 0

Answer:

Step-by-step explanation:

7 triangle calls in every 140cm

Number of cm per triangle call

140 / 7 = 20 cm per triangle

Number of rectangles in 220 cm :

220 cm / 20

= 11 triangle calls

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A shopper buys 3 notebook for $5 each the percent of sales tax is 8% how much is the total sale

Vlad1618 [11]

All you have to do is 3×5=15
then 8÷8=1 so 16 dollars

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3 years ago

How many quarters in $100

Y_Kistochka [10]

400 quarters

$1 = 4q

4q • 100 = 400

400q=$100

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3 years ago

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Find the average value of f over region

SVETLANKA909090 [29]

$D$ is a right triangle with base length 1 and height 8, so the area of $D$ is $\dfrac12(1)(8)=4$ .

The average value of $f(x,y)$ over $D$ is given by the ratio

$\dfrac{\displaystyle\iint_Df(x,y)\,\mathrm dA}{\displaystyle\iint_D\mathrm dA}$

The denominator is just the area of $D$ , which we already know. The average value is then simplified to

$\displaystyle\frac74\iint_Dxy\,\mathrm dA$

In the $x,y$ -plane, we can describe the region $D$ as all points $(x,y)$ that lie between the lines $y=0$ and $y=8x$ (the lines which coincide with the triangle's base and hypotenuse, respectively), taking $0\le x\le1$ . So, the integral is given by, and evaluates to,

$\displaystyle\frac74\int_{x=0}^{x=1}\int_{y=0}^{y=8x}xy\,\mathrm dy\,\mathrm dx=\frac78\int_{x=0}^{x=1}xy^2\bigg|_{y=0}^{y=8x}\,\mathrm dx$
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3 0

3 years ago

How to solve this<br><img src="https://tex.z-dn.net/?f=540in%20%3D%20%20%5C%3A%20yd" id="TexFormula1" title="540in = \: yd" alt

Gnom [1K]

Answer:

15 yds

Step-by-step explanation:

12 in = 1ft

3 ft = 1yd

to convert

540 in * 1ft/12 in * 1yd /3 ft = (540 * 1 * 1)/ (12*3) = 540/36 =15 yds

all the units canceled except for yds

5 0

3 years ago

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Adult female height is normally distributed with a mean of 65.3 inches and a standard deviation of 2.32 inches. a) If an adult f

emmasim [6.3K]

Answer:

0.0423 is the probability that the adult female has a height less than 61.3 inches.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 65.3 inches

Standard Deviation, σ = 2.32 inches

We are given that the distribution of adult female height is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

P(adult female has a height less than 61.3 inches)

$P( x < 61.3) = P( z < \displaystyle\frac{61.3 - 65.3}{2.32}) = P(z < -1.7241)$

Calculation the value from standard normal z table, we have,

$P(x < 61.3) =0.0423 = 4.23\%$

0.0423 is the probability that the adult female has a height less than 61.3 inches.

5 0

3 years ago