Problem 3: Let x = price of bag of pretzels Let y = price of box of granola bars
We have Lesley's purchase: 4x+2y=13.50
And Landon's: 1x+5y=17.55
We can use the elimination method. Let's negate Landon's purchase by multiplying by -1. -1x-5y=-17.55
We add this four times to Lesley's purchase to eliminate the x variable.
2y-20y=13.50-70.2
-18y=-56.7
y = $3.15 = Price of box of granola bars
Plug back into Landon's purchase to solve for pretzels.
x+5*3.15=17.55
x+15.75=17.55
x = $1.80 = price of bag of pretzels
Problem 4.
Let w = number of wood bats sold
Let m = number of metal bats sold
From sales information we have: w + m = 23
24w+30m=606
Substitution works well here. Solve for w in the first equation, w = 23 - m, and plug this into the second.
24*(23-m)+30m=606
552-24m+30m=606
6m=54
m=9 = number of metal bats sold
Therefore since w = 23-m, w = 23-9 = 14. 14 wooden bats were sold.
Answer:
C) y=13+15x
Step-by-step explanation:
y=13+15x
Formula
1/2 (b×h)
plug in
1/2 (6×3)
1/2 (18)
9 ft squared.
always remember measurement of the shape, square your answer because your finding area and formulas. the numbers on the side are to distract you.
Answer:48
Step-by-step explanation:
Total number of students=397
Students that travelled in a car=29
Let the students that travelled in a bus be represented by y.
Since 8 buses were filled, it will be 8y for total students
8y + 29= 397
8y= 397-29
8y= 368
Divide both side by 8
8y/8=368/8
y = 46
Number of students in each bus is 46
Answer: 9
Step-by-step explanation: Multiply 3 to itself and you will get nine.
3^2
