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faust18 [17]
2 years ago
7

Anyone know the answer?​

Mathematics
2 answers:
VladimirAG [237]2 years ago
7 0
Yea what they said lol
MariettaO [177]2 years ago
3 0

Answer:

It's 15^7/4

Basically just switch what you have for b and c and it'll be right

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paul was given 2760$ to buy toys for a group of children.A)what would be the greatest number of toys paul could buy if each toy
Radda [10]

Answer:

2760 ÷ 9 = x

x = 306

306(9) = 2754

2760 - 2754 = 6

Have a good day! :)

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2 years ago
What angle is complementary to 2 ?
Zarrin [17]

Answer:

number 4 i gess

Step-by-step explanation:

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3 years ago
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What are the all solutions to the following equation? |3x+2|=17
Rom4ik [11]

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2 years ago
How many students must be randomly selected to estimate the mean weekly earnings of students at one college? We want 95% confide
kari74 [83]

Answer:

The sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

CI=\bar x\pm z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The margin of error of a (1 - <em>α</em>)% confidence interval for population mean (<em>μ</em>) is:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

The information provided is:

<em>σ</em> = $60

<em>MOE</em> = $2

The critical value of <em>z</em> for 95% confidence level is:

z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96

Compute the sample size as follows:

MOE=z_{\alpha/2}\times \frac{\sigma}{\sqrt{n}}

       n=[\frac{z_{\alpha/2}\times \sigma }{MOE}]^{2}

          =[\frac{1.96\times 60}{2}]^{2}

          =3457.44\\\approx 3458

Thus, the sample of students required to estimate the mean weekly earnings of students at one college is of size, 3458.

8 0
3 years ago
These four numbers are plotted on a number line: -2/3 5/8 -3/5 -1/2 Which is the correct ordering on the number line, from left
Yuki888 [10]

Answer:

-2/3 -3/5 -1/2 3/8

..................……

3 0
2 years ago
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